Question

美好的一天我有一个显示公告的页面。
我想在每一分钟检查公告是否有任何变化如果有任何更改，我应该更新页面的内容因此，我需要将旧的公告发送回控制器进行检查但我的问题是我不知道如何将整个对象从数据库发送回控制器。
（我只能发送普通的单一数据类型，如string，int等）

以下是我的代码的概述
先感谢您。

我的观点（php）

<div class="row " id="tabapp_news">
    <div class="container">
        <div class='tickercontainer'>
            <div class='mask'>
              <ul id="telop">
                <?php 
                foreach ($announces as $announce) {
                    echo '<li>' . $announce->comment . '</li>';
                }
                ?>
              </ul>
            </div>
        </div>
  </div>
</div>

控制器

public function actionIndex()
{
    $announces = [];
    $desk_id = Yii::$app->request->get(DESK_KEYWORD);
    if (!empty($desk_id)) {
        $desk = Desk::find()
                    ->where((['id' => $desk_id]))
                    ->one();
        if ($desk) {
            $announces = Announce::getOpeningAnnouncesByDesk($desk->id);
        }
    }
    return $this->render('announce', [
            'announces' => $announces,
            'desk' => $desk,
            ]);
}


public function actionCheckNewAnnounce()
{
    $announces = Yii::$app->request->post('announces');;
    $desk_id = Yii::$app->request->get(DESK_KEYWORD);
    if (!empty($desk_id)) {
        $desk = Desk::find()
                    ->where((['id' => $desk_id]))
                    ->one();
        if ($desk) {
            $new_announces = Announce::getOpeningAnnouncesByDesk($desk->id);

            if (array_diff($new_announces, $announces)) {
                return $this->render('announces', [
                    'announces' => $new_announces,
                    'desk' => $desk,
                ]);
            }
        }
    }
    return "";
}

我的javascript / ajax

var interval = setInterval(function(){
        $.ajax({
            url: '/check-new-single',
            dataType: 'html',
            data: {announces: $("#info").data('announces')},
            method: 'post',
            success: function(response) {
                if (response != "") {
                    $('#telop').empty();
                    $('#telop').append(response);
                }
            },
            error: function(XMLHttpRequest, textStatus, errorThrown) {
                console.log("ajax communication failure.");
            }
        });
    }, 60000);

Answer 1

您的观点（index.php）

<div class="row " id="tabapp_news">
<div class="container">
    <div class='tickercontainer'>
        <div class='mask'>
          <ul id="telop">
            <?php 
             echo $this->render('annnounce',['announces' => $announces])
            ?>
          </ul>
        </div>
    </div>

查看（announce.php）

<?php
    foreach ($announces as $announce) {
                echo '<li>' . $announce->comment . '</li>';
    }
?>

<强> JS

var interval = setInterval(function(){
    $.ajax({
        url: '/check-new-announce',
        dataType: 'html',
        data: {announces: $("#info").data('announces')},
        method: 'post',
        success: function(response) {
            if (response != "") {
                $('#telop').html(response);
            }
        },
        error: function(XMLHttpRequest, textStatus, errorThrown) {
            console.log("ajax communication failure.");
        }
    });
}, 60000);

控制器操作

更改渲染以渲染Ajax

public function actionCheckNewAnnounce()
{
    $announces = Yii::$app->request->post('announces');;
    $desk_id = Yii::$app->request->get(DESK_KEYWORD);
    if (!empty($desk_id)) {
        $desk = Desk::find()
                ->where((['id' => $desk_id]))
                ->one();
        if ($desk) {
           $new_announces = Announce::getOpeningAnnouncesByDesk($desk->id);

            if (array_diff($new_announces, $announces)) {
                return $this->renderAjax('announce', [
                   'announces' => $new_announces,
               ]);
           }
       }
   }
   return "";
}

通过ajax将对象从php（视图）发送到控制器（php）

1 个答案: