我希望在两个实体,消费者和政策之间建立一对多的关系。一个消费者应该有几个政策。
这是我想要的Consumer JSON对象的一个例子:
<Icon.ToolbarAndroid
titleColor={'#000000'}
style={{
height: 56,
alignSelf: 'stretch',
width: 20
}}
iconColor={"#fff"}
iconSize={26}
rtl={true}
navIconName={"more-vert"}
contentInsetStart={50}
actions={[{title: 'Settings', show: 'always'}, {title: 'Settings 2', show: 'always'}]} />
这是我到目前为止所做的:
政策实体
{
id : 1,
name : "Peter",
endpoint: "123.456.778",
policies: [
{
id : 1,
name: "policy 01"
},
{
id : 2,
name: "policy 02"
}
]
}
消费者实体
@Entity
public class Policy {
@Id
@GeneratedValue
@Column(name = "id")
private Integer id;
@Column(name = "name")
private String name;
//getters and setters
}
我认为这并不难,但我现在尝试几个小时并且无法完成它。我是Spring的新手,所以如果有人能够帮助我,我会非常感激!
答案 0 :(得分:1)
@Entity
public class Consumer {
@OneToMany(mappedBy = "consumer")
private List<Policy> policies;
}
@Entity
public class Policy {
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn("consumer_id")
private Consumer consumer;
}
fetch = FetchType.LAZY
不是必需的,但是可取的。
我在这里提供了一些基础知识
what is @JoinColumn and how it is used in Hibernate
如果您想要Policy
没有Consumer
:
您可以使用联接表
@Entity
public class Consumer {
@OneToMany
private List<Policy> policies;
}
@Entity
public class Policy {
}
单向关系(Policy
表格会有consumer_id
列,但Policy
类没有Consumer
)
@Entity
public class Consumer {
@OneToMany
@JoinColumn("consumer_id")
private List<Policy> policies;
}
@Entity
public class Policy {
}
另外,请注意,如果您想使用Policy
作为参考(来自字典),则需要@ManyToMany
。
答案 1 :(得分:0)
试试这段代码:)
您的消费者类
<div class="info-description">
请注意,在映射的旁边,您应该使用数据库中引用Policy的列的名称,因此,如果它没有policyId,请使用您为其指定的名称
您的政策类
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