Question

我试着在postgres下面查询：

select * from user u join
    user_func uf on u.pk = uf.user_pk
where uf.functions in ('UPDATE_MODEL', 'UPDATE_USER')
            and u.perfil in ('ADMIN', 'MANAGER');

但是这会返回UPDATE_MODEL和UPDATE_USER中的任何匹配，当用户在user_func中有两个函数时，我只想要所有匹配。你帮我吗？感谢。

例如。用户ID = 1在user_func中只有UPDATE_MODEL，它出现在结果中，对我来说是错误的。此外，用户ID = 2会显示在结果中，但是正确，因为它具有所有功能（＆＃39; UPDATE_MODEL＆＃39;，＆＃39; UPDATE_USER＆＃39;）。

Answer 1

select * from user u 
join user_func uf on u.pk = uf.user_pk
join user u2 on u.id = u2.id
join user_func uf2 on u2.pk = uf2.user_pk
where uf.functions = 'UPDATE_MODEL' 
AND  uf2.functions = 'UPDATE_USER'
AND u.perfil in ('ADMIN', 'MANAGER');

Answer 2

SELECT * FROM users 
WHERE u IN (SELECT u from user_func 
          WHERE functions IN ('UPDATE_MODEL', 'UPDATE_USER')
          group by u
          having (count(*) > 1) )
AND perfil in ('ADMIN', 'MANAGER');

看看这是否有效。

Answer 3

select * from user u join
(
    select uf1.* from user_func uf1
    join user_func uf2 on uf1.user_pk=uf2.user_pk and uf1.functions <> uf2.functions 
    where uf1.functions in('UPDATE_MODEL', 'UPDATE_USER')
) as T
on u.pk = T.user_pk
where and u.perfil in ('ADMIN', 'MANAGER');

SQL查询所有项匹配

3 个答案: