group_by返回重复的键

Question

Python 3.6 我有一个简单的对象列表：

for obj in obj_ts:
    print(obj['address'])

这告诉我：

mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mhRhCZBUP1BsrL6xuXSeAeCNnXcoBHWKAB
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR

然后我想按这个对象分组：

for address, t_list in itertools.groupby(obj_ts, key=lambda obj: obj['address']):
    print(address)

但我得到3组而不是2组。

mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR
mhRhCZBUP1BsrL6xuXSeAeCNnXcoBHWKAB
mwpJCSEEkphA1utQGA2Y9Vx8cufv85CgpR

Answer 1

评论解决方案：

  

正如groupby docs的第1段所述，你需要   在传递数据之前对数据（具有相同的键功能）进行排序   GROUPBY

https://docs.python.org/3/library/itertools.html#itertools.groupby