Question

我找到一个以查找节点索引的方式处理xml的好方法有问题。例如：

String test = '''
<Library>
 <Books>
  <Book>
   <Title>Hello</Title>
   <Author>John Doe</Author>
   <Publication>2008</Publication>
  </Book>
  <Book>
   <Title>Bye</Title>
   <Author>Mary Derp</Author>
   <Publication>2011</Publication>
  </Book>
  [...]
 </Books>
</Library>'''

def xml = new XmlSlurper().parseText(test)

现在我想知道是否有任何书的标题是＆＃34;再见＆＃34;而作者是＃34; Mary Derp＆＃34;。如果是，它应该告诉我节点的索引。所以在这种情况下节点[1]。

Answer 1

＆＃39;实测＆＃39;将包含匹配书籍的索引列表：

String test = '''
<Library>
 <Books>
  <Book>
   <Title>Hello</Title>
   <Author>John Doe</Author>
   <Publication>2008</Publication>
  </Book>
  <Book>
   <Title>Bye</Title>
   <Author>Mary Derp</Author>
   <Publication>2011</Publication>
  </Book>
   <Book>
   <Title>Hello</Title>
   <Author>Mary Derp</Author>
   <Publication>2012</Publication>
  </Book>
  <Book>
   <Title>Bye</Title>
   <Author>Mary Derp</Author>
   <Publication>2012</Publication>
  </Book>
 </Books>
</Library>'''

def found = []
def Library = new XmlSlurper().parseText(test)
Library.Books.Book.eachWithIndex { def book, int i ->
    if (book.Title == 'Bye' && book.Author == 'Mary Derp') {
        found += i
    }
}
println found

所以在这种情况下它会返回： [1,3]

Answer 2

请考虑以下事项。它将书籍映射到布尔值（通过collect），然后找到第一个true值。（修改：简化）

def Library = new XmlSlurper().parseText(test)

def index = Library.Books.Book.collect {
    (it.Title == 'Bye' && it.Author == 'Mary Derp')
}.indexOf(true)

assert 1 == index

Groovy：节点的索引

2 个答案: