Question

function categoriesIdsFunction($ids){
    //I try with preg_replace remove if exists all character before _
    $ids = preg_replace('/^[^_]*_\s*/', '', $ids);

    $ids = preg_replace('/\s+/', '', $ids);
      return "in ('" . str_replace(",","','",$ids) . "') ";
}

$categories_in_article = "267,267_463,267_462";

$categories_in_article_return = categoriesIdsFunction($categories_in_article);

通过我的代码，我接受了这一点：（＆＃39; 463＆＃39;，＆＃39; 267_462＆＃39;），我尝试使用preg_replace remove如果在_之前存在所有字符（$ ids = preg_replace（＆＃39; / ^ [^ ] * \ s * /＆＃39;，＆＃39;＆＃39 ;，$ ids）;）

我需要这个回报：在（＆＃39; 267＆＃39;，＆＃39; 463＆＃39;，＆＃39; 462＆＃39;）

Answer 1

我无法得到你需要返回的东西。如果你需要一个数组，你可以试试这个：

$result = array_map(function (string $item) {
    return preg_replace('.+_', '', $item);
}, explode(',', $categoriesInArticle));

另外，您可以implode(',', $result)获取不带_符号的字符串。

Answer 2

你想要的是这样吗？ out put：in ('267','463','462')

function test2()
{
    $categories_in_article = "267,267_463,267_462";
    $stringArray = explode ( "," , $categories_in_article);
    $categories_in_article_return = "in (";
    foreach($stringArray as $string){
        $categories_in_article_return .=       
        $this->categoriesIdsFunction($string).",";
    }
$categories_in_article_return = rtrim($categories_in_article_return,",");
$categories_in_article_return .= ") ";
echo $categories_in_article_return;
}

    function categoriesIdsFunction($ids){
        //I try with preg_replace remove if exists all character before _
        $ids = preg_replace('/^[^_]*_\s*/', '', $ids);

        $ids = preg_replace('/\s+/', '', $ids);
        return "'".str_replace(",","','",$ids)."'";
    }

删除如果_之前存在所有字符

2 个答案: