Question

我被困在一个点，我有两个像这样的数组变量

$name = @("A","B","C")

$roll = @("1","2","3")

我正在尝试使用此数据制作csv文件。我正在使用此代码

$name = @("A","B","C")
$roll = @("1","2","3")
$report = New-Object psobject
$report | Add-Member -MemberType NoteProperty -Name "Name" -Value "$name"
$report | Add-Member -MemberType NoteProperty -Name "Roll" -Value "$roll"
$report | Export-Csv -Path "C:\Users\Abby\Desktop\r.csv" -NoTypeInformation

但我有这样的输出

NAME |辊

A B C | 1 2 3

我希望我的输出像这样

NAME |辊

A | 1

B | 2

C | 3

任何人都知道怎么做这些......请帮助我...... :(

Answer 1

您当前的代码正在创建对象，并将数组$name和$roll添加为单个条目。

听起来你想要一个数组中每个值的条目。假设数组长度相同，您可以迭代值：

$name = @("A","B","C")
$roll = @("1","2","3")

foreach($i in 0..($name.Count -1)){
    [array]$report += [pscustomobject] @{
        Name = $name[$i]
        Roll = $roll[$i]
    }
}

# screen output
# $report | Format-Table

$report | Export-Csv -Path "C:\Users\Abby\Desktop\r.csv" -NoTypeInformation

屏幕输出

Name Roll
---- ----
A    1
B    2
C    3

Answer 2

试试这个：

$name = "A","B","C"
$roll = "1","2","3" 
$index = 0
$name | %{[pscustomobject]@{Name=$_;Roll=$roll[$index++]}} |Export-csv "C:\Users\Abby\Desktop\r.csv" -NoType

如何从powershell在csv文件上创建换行符

2 个答案: