如何从xml节点“OuterXml”读取数据或属性

时间:2017-11-01 11:34:53

标签: c# xml

<?xml-stylesheet href="latest_ob.xsl" type="text/xsl"?>
<current_observation version="1.0" >
    </image>
    <suggested_pickup>15 minutes after the hour</suggested_pickup>
    <suggested_pickup_period>60</suggested_pickup_period>
    <temp_f>44.0</temp_f>
    <temp_c>6.7</temp_c>
    <relative_humidity>55</relative_humidity>
    <wind_string>North at 6.9 MPH (6 KT)</wind_string>
    <wind_dir>North</wind_dir>
    <wind_degrees>340</wind_degrees>
    <wind_mph>6.9</wind_mph>
    <wind_kt>6</wind_kt>
    <pressure_string>1025.2 mb</pressure_string>
    <pressure_mb>1025.2</pressure_mb>
    <pressure_in>30.28</pressure_in>
    <dewpoint_string>28.9 F (-1.7 C)</dewpoint_string>
    <dewpoint_f>28.9</dewpoint_f>
    <dewpoint_c>-1.7</dewpoint_c>
</current_observation>

我想从上面的xml数据中获取一些属性wind_dirwind_kt等。我试过这个:

var dayt = GetXMLAsString(WeatherXML);
XDocument doc = XDocument.Parse(dayt);

var r = from element in doc.Elements()
        where element.Name == "latitude"
        select element;

foreach (var item in r)
{
    Console.WriteLine(item.Value);
}

我希望将这些数据转换为数组或模型,以将其发送到ajax结果。

2 个答案:

答案 0 :(得分:0)

我之前已尝试过,但保留了#34; .value&#34;:

var a =来自doc.Descendants中的哈希值(&#34;纬度&#34;)                         select hash.value;

当我尝试如下时,我得到了正确的结果:   XmlDocument WeatherXML = new XmlDocument();                 WeatherXML.Load(读取器);

            var dayt = GetXMLAsString(WeatherXML);
            XDocument doc = XDocument.Parse(dayt);

var a =来自doc.Descendants中的哈希值(&#34;纬度&#34;)                     选择哈希;

            var asdd = from hash in doc.Descendants("current_observation")
                    select hash;

答案 1 :(得分:0)

使用System.Xml.Linq命名空间,我们有一组方便的方法来调用。 在您的情况下,以下代码可以提供帮助:

var doc = XDocument.Parse(WeatherXML);
var value = from e in doc.Elements()
            where e.Name == "wind_kt"
            select e.Value;