Question

想象一下下表（它有其他行，但下面显示的是在查询中使用的那些），

+-------------------+-----------------+---------------------+ 
| INTERVAL_QUANTITY | INTERVAL_UOM_ID | LAST_UPDATED_STAMP  |
+-------------------+-----------------+---------------------+ 
| 10                | TF_wk           | 2017-10-31 17:21:40 |
| 20                | TF_mon          | 2017-10-30 17:21:40 | 
| 30                | TF_day          | 2017-10-29 17:21:40 |
+-------------------+-----------------+---------------------+

关键

TF_wk =＆gt; WEEK
TF_mon =＆gt;个月
TF_day =＆gt; DAY

现在，我有以下查询，

SELECT
    *
FROM
    product_maint 
WHERE
    ( INTERVAL_UOM_ID = 'TF_day' OR INTERVAL_UOM_ID = 'TF_wk' OR INTERVAL_UOM_ID = 'TF_mon' ) 
    AND DATEDIFF( DATE( DATE_ADD( LAST_UPDATED_STAMP, INTERVAL INTERVAL_QUANTITY DAY ) ), DATE( NOW( ) ) ) <= 0;

问题是，当它选择INTERVAL_UOM_ID TF_wk INTERVAL_QUANTITY 10 70行时，实际需要在10天内添加不是INTERVAL_UOM_ID天，同样当TF_mon为INTERVAL_QUANTITY且20为560时需要在package helloworldexample; import java.util.Iterator; import java.util.List; import java.util.Scanner; import org.hibernate.HibernateException; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.Transaction; import org.hibernate.boot.registry.StandardServiceRegistryBuilder; import org.hibernate.cfg.Configuration; import org.hibernate.service.ServiceRegistry; public class HelloWorldExample { private static SessionFactory factory; private static ServiceRegistry registry; public static void main(String[] args) { Scanner in = new Scanner(System.in); String m = ""; System.out.println("Enter a message: "); m = in.nextLine(); try{ Configuration conf = new Configuration().configure(); registry = new StandardServiceRegistryBuilder().applySettings( conf.getProperties()).build(); factory = conf.buildSessionFactory(registry); } catch (Throwable ex){ System.err.println("Failed to create session factory object"+ex); throw new ExceptionInInitializerError(ex); } Session session = factory.openSession(); Transaction tx = null; Short msgId = null; try{ tx=session.beginTransaction(); Message msg = new Message(m); msgId = (Short) session.save(msg); List messages = session.createQuery("FROM Message").list(); for(Iterator iterator = messages.iterator(); iterator.hasNext();){ Message message = (Message)iterator.next(); System.out.println("message: "+message.getMessage()); } tx.commit(); }catch(HibernateException e){ if(tx != null) tx.rollback(); e.printStackTrace(); }finally{ session.close(); } StandardServiceRegistryBuilder.destroy(registry); } }天添加（假设我的所有数学是正确的。）

我将如何实施此逻辑？

Answer 1

您需要分别检查每个间隔。我想你想要：

WHERE ( INTERVAL_UOM_ID = 'TF_day' AND
        LAST_UPDATED_STAMP > CURDATE() - INTERVAL INTERVAL_QUANTITY DAY 
      ) OR
      ( INTERVAL_UOM_ID = 'TF_wk' AND 
        LAST_UPDATED_STAMP > CURDATE() - INTERVAL INTERVAL_QUANTITY WEEK 
      ) OR
      ( INTERVAL_UOM_ID = 'TF_mon' AND
        LAST_UPDATED_STAMP > CURDATE() - INTERVAL INTERVAL_QUANTITY MONTH 
      )

请注意，我已将NOW()更改为CURDATE()。我不认为时间组件对你想做的事情很重要。另请注意，我将逻辑更改为仅使用日期算法。

如何更改依赖于表中字段的date_add间隔类型？

1 个答案: