我想将电子邮件#$%#$ @ b@#$#$2344324.com清理为a@b.com。
我尝试过但失败了
echo filter_var(“a#$%#$ @ b@#$#$2344324.com”,FILTER_SANITIZE_EMAIL); //结果:#$%#$ @ b @#$#$ 2344324.com
我需要修剪电子邮件中的特殊字符(清理以删除特殊字符)。我使用下面的代码,但我没有成功。
$string = preg_replace("/^[a-zA-Z0-9._%+-]+@(?:[a-zA-Z0-9-]+\.)+[a-zA-Z]{2,4}$/", "", "a#$%#$@b@#$#$2344324.com");
echo $string;//result: a@b.com -- unwanted characters trimmed here.
答案 0 :(得分:1)
此处已有基于RFC的解决方案:http://fightingforalostcause.net/misc/2006/compare-email-regex.php
function is_valid_email_address($email){
$qtext = '[^\\x0d\\x22\\x5c\\x80-\\xff]';
$dtext = '[^\\x0d\\x5b-\\x5d\\x80-\\xff]';
$atom = '[^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c'.
'\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+';
$quoted_pair = '\\x5c[\\x00-\\x7f]';
$domain_literal = "\\x5b($dtext|$quoted_pair)*\\x5d";
$quoted_string = "\\x22($qtext|$quoted_pair)*\\x22";
$domain_ref = $atom;
$sub_domain = "($domain_ref|$domain_literal)";
$word = "($atom|$quoted_string)";
$domain = "$sub_domain(\\x2e$sub_domain)*";
$local_part = "$word(\\x2e$word)*";
$addr_spec = "$local_part\\x40$domain";
return preg_match("!^$addr_spec$!", $email) ? true : false;
}