Question

我有一个JSON结构，如下所示

 $json = '{"Number1":"{\"answerPhrase\":\"\\nTEXT,\\nTEXT 
TEXT\\n\",\"dateUpdatedInMillisecond\":1234}"}';

当尝试提取文本和数字时，我可以执行第一步并且它可以工作，但嵌套的JSON具有\\n并且它不会将文本作为输出

PHP代码如下

$result = json_decode($json);
print_r($result);
echo "<br>";
foreach($result as $key=>$value){
    echo $key.$value;
    echo "<br>";
    $result_nest = json_decode($value);
    echo  $result_nest->answerPhrase;
    echo "<br>";

为什么我不能用短语中的文字？它在文本没有\\n

时有效

Answer 1

您可以尝试以下方法。您可以将\ n替换为其他一些字符。如果要在浏览器中显示输入，则可以用\替换\ n。请尝试下面的代码，让我知道它是否适合您。

<?php
$json = '{"Number1":"{\"answerPhrase\":\"\\nTEXT,\\nTEXT TEXT\\n\",\"dateUpdatedInMillisecond\":1234}"}';

$result = json_decode($json);
print_r($result);
echo "\n";
foreach($result as $key=>$value){
    echo $key.$value;
    echo "<br>";
    $value = preg_replace("/\\n/", "___n___", $value);
    $result_nest = json_decode($value);
    $result_nest->answerPhrase = preg_replace("/___n___/", "\n", $result_nest->answerPhrase);

    echo  $result_nest->answerPhrase;
    echo "<br>";
}

Answer 2

喜欢在解码之前修复json然后解码子json。你可以在循环中做第二步

    function test2()
    {
        $string = '{"Number1":"{\"answerPhrase\":\"\\nTEXT,\\nTEXT
TEXT\\n\",\"dateUpdatedInMillisecond\":1234}"}';


        $json = $this->decodeComplexJson($string);
        $number = $json->Number1;
        //Put this in a loop if you want
        $decodedNumber = $this->decodeComplexJson($number);
        var_dump($decodedNumber);
        echo $decodedNumber->answerPhrase;

    }

    function decodeComplexJson($string) { # list from www.json.org: (\b backspace, \f formfeed)
        $string = preg_replace("/[\r\n]+/", " ", $string);
        $json = utf8_encode($string);
        $json = json_decode($json);
        return $json;
    }

如何在php中使用\\ n进行JSON解码

2 个答案: