Question

为什么我只获得第一个字符而不是标签中的整个字符串？

#This for multiple URL
import urllib2
from bs4 import BeautifulSoup
import requests
import itertools

with open('site_test.txt') as site_test:
    sites = (line.strip() for line in site_test)
    for site in sites:
        site = urllib2.urlopen(site)
        soup = BeautifulSoup(site, "html.parser")

        for x, y, z, e in itertools.izip(soup.find_all('h1')[0], soup.find_all('p')[1], soup.find_all('p')[2].text, soup.find_all('p')[3].text):
            print x+"--"+y+"--"+z+"--"+e
            #Result for x is 'full name'
            #           y is 'occupation'

结果
全名 - 职业 - 0 - a

'全名'和'职业'工作正常 '0'是第一个字符：它应该是'000-345-678'
'a'是第一个字符：它应该是'alex@email.com'

但是当我在不同的任务中执行它时，只有一个URL。它工作得很好

#This for 1 raw_input URL
import urllib2
from bs4 import BeautifulSoup

site = raw_input("Link: ")
page = urllib2.urlopen(site)
soup = BeautifulSoup(page, "html.parser")

x= soup.h1.string
y= soup.find_all('p')[1].text
z= soup.find_all('p')[2].text
e= soup.find_all('p')[3].text

print x+"--"+y+"--"+z+"--"+e

Answer 1

错误地有第二个循环

import urllib2
from bs4 import BeautifulSoup
import requests
import itertools

with open('site_test.txt') as site_test:
sites = (line.strip() for line in site_test)
for site in sites:
    site = urllib2.urlopen(site)
    soup = BeautifulSoup(site, "html.parser")

    x= soup.h1.string
    y= soup.find_all('p')[1].text
    z= soup.find_all('p')[2].text
    e= soup.find_all('p')[3].text

    print x+"--"+y+"--"+z+"--"+e

为什么只获得字符串的第一个字符？

1 个答案: