C#Json对象词典

时间:2017-10-31 23:25:42

标签: c# json json.net deserialization

我想带一些Json并将其解析为一组键/值对,但有些值本身就是字典。我尝试了通常的Newtonsoft反序列化。它很接近,但不是很正确。最终结果必须是字典,而不是强类型类。

这是Json的一些例子:

{
  "JobNumber": 1010,
  "Asset": null,
  "JobNotes": [
    {
      "NoteText": "It's not working.",
      "NoteType": "Complaint"
    },
    {
      "NoteText": "Needs to be fixed",
      "NoteType": "Job"
    }
  ]
}

这是我用来反序列化的代码:

        var json = File.ReadAllText(@"c:\temp\job.json");
        var result = JsonConvert.DeserializeObject<Dictionary<string, object>>(json);

结果几乎是正确的,但带有“JobNotes”键的项的值只是json字符串。我希望解析器递归并将内部Json反序列化为另一个字符串和对象字典。 有没有办法可以用Newtonsoft库做到这一点?或者,是否有其他库可以解决这个问题?我可以挂钩解析方法来覆盖那个时间点的功能吗?

3 个答案:

答案 0 :(得分:1)

这可以通过一点递归来完成。我会将IsJson定义为学术练习。 :)

Dictionary<string, object> RecursiveDeserialize(string json)
{
     var result = JsonConvert.DeserializeObject<Dictionary<string, object>>(json);
     foreach (var pair in result.ToArray())
     {
         if(IsJson(pair.Value))
         {
             result[pair.Key] = RecursiveDeserialize(pair.Value);
         }
     }
     return result;
}

答案 1 :(得分:1)

这是@ DanielKeogh代码的修改版本。效果很好。

class Program
{
    static void Main(string[] args)
    {
        var json = File.ReadAllText(@"c:\temp\job3.json");
        var result = JsonConvert.DeserializeObject<Dictionary<string, object>>(json);
        RecurseDeserialize(result);
    }

    private static void RecurseDeserialize(Dictionary<string, object> result)
    {
        //Iterate throgh key/value pairs
        foreach (var keyValuePair in result.ToArray())
        {
            //Check to see if Newtonsoft thinks this is a JArray
            var jarray = keyValuePair.Value as JArray;

            if (jarray != null)
            {
                //We have a JArray

                //Convert JArray back to json and deserialize to a list of dictionaries
                var dictionaries = JsonConvert.DeserializeObject<List<Dictionary<string, object>>>(jarray.ToString()); 

                //Set the result as the dictionary
                result[keyValuePair.Key] = dictionaries;

                //Iterate throught the dictionaries
                foreach (var dictionary in dictionaries)
                {
                    //Recurse
                    RecurseDeserialize(dictionary);
                }
            }
        }
    }
}

这个经过修改的Json显示了它的深度:

{
  "JobNumber": 1010,
  "Asset": null,
  "JobNotes": [
    {
      "NoteText": "It's not working.",
      "NoteType": "Complaint"
    },
    {
      "NoteText": "Needs to be fixed",
      "NoteType": "Job",
      "JobNoteNotes": [
        {
          "Something": 1,
          "Something2": "Test"
        }
      ]
    }
  ]
}

结果会结束三个字典,这样我就可以按键获得“Something”值。

答案 2 :(得分:-1)

将此对象用于json字符串

&#13;
&#13;
public class JobNote
{
    public string NoteText { get; set; }
    public string NoteType { get; set; }
}

public class ListJob
{
    public int JobNumber { get; set; }
    public object Asset { get; set; }
    public List<JobNote> JobNotes { get; set; }
}
&#13;
&#13;
&#13;

然后你可以反序列化它