使用discord.js和ytdl-core播放音频文件

Question

我尝试使用ytdl和discord.js下载并播放从youtube获取的音频文件：

        ytdl(url)
            .pipe(fs.createWriteStream('./music/downloads/music.mp3'));

        var voiceChannel = message.member.voiceChannel;
        voiceChannel.join().then(connection => {
            console.log("joined channel");
            const dispatcher = connection.playFile('./music/downloads/music.mp3');
            dispatcher.on("end", end => {
                console.log("left channel");
                voiceChannel.leave();
            });
        }).catch(err => console.log(err));
        isReady = true

我成功设法在没有ytdl部分（ytdl(url).pipe(fs.createWriteStream('./music/downloads/music.mp3'));）的./music/downloads/中播放mp3文件。但是当该部分在代码中时，机器人就会加入并离开。

以下是ytdl部分的输出：

Bot has started, with 107 users, in 43 channels of 3 guilds.
joined channel
left channel

这是没有ytdl部分的输出：

Bot has started, with 107 users, in 43 channels of 3 guilds.
joined channel
[plays mp3 file]
left channel

为什么会这样，我该如何解决？

Answer 1

当您需要播放音频流时，请使用playStream代替playFile。

viewBTopConstraints?.isActive = false
newViewBTopConstraints?.isActive = true

Answer 2

  

您正在以低效的方式进行操作。读写之间没有同步。   
  或者，等待文件写入文件系统，然后再阅读！

直接流式传输

将 YTDL 的视频输出重定向到调度程序，该调度程序将首先转换为opus音频数据包，然后再从计算机流式传输到Discord。

message.member.voiceChannel.join()
.then(connection => {
    console.log('joined channel');

    connection.playStream(YTDL(url))
    // When no packets left to sent leave the channel.
    .on('end', () => {
        console.log('left channel');
        connection.channel.leave();
    })
    // Handle error without crashing the app.
    .catch(console.error);
})
.catch(console.error);

FWTR（先写，然后读）

您使用的方法非常接近成功！
但是失败是当您不同步读/写时。

var stream = YTDL(url);

// Wait until writing is finished
stream.pipe(fs.createWriteStream('tmp_buf_audio.mp3'))
.on('end', () => {
    message.member.voiceChannel.join()
    .then(connection => {
        console.log('joined channel');

        connection.playStream(fs.createReadStream('tmp_buf_audio.mp3'))
        // When no packets left to sent leave the channel.
        .on('end', () => {
            console.log('left channel');
            connection.channel.leave();
        })
        // Handle error without crashing the app.
        .catch(console.error);
    })
    .catch(console.error);
});