Question

我正在写一个php页面，让用户将他的个人资料图片上传到数据库sql但我得到这些错误我尝试了很多我在网上找到的解决方案，但我不知道如何修复我的代码，我会真的感谢您的时间我是一名新开发者。提前谢谢你：

错误是：

( ! ) Warning: file_get_contents(https://api.imgur.com/3/image): failed to open stream: HTTP request failed! HTTP/1.1 403 Permission Denied in C:\wamp64\www\final-project\classes\Image.php on line 22
Call Stack
#   Time    Memory  Function    Location
1   0.0009  381752  {main}( )   ...\my-account.php:0
2   0.0175  439648  Image::uploadImage( )   ...\my-account.php:33
3   0.0224  789608  file_get_contents ( )   ...\Image.php:22

( ! ) Notice: Trying to get property of non-object in C:\wamp64\www\final-project\classes\Image.php on line 25
Call Stack
#   Time    Memory  Function    Location
1   0.0009  381752  {main}( )   ...\my-account.php:0
2   0.0175  439648  Image::uploadImage( )   ...\my-account.php:33

( ! ) Notice: Trying to get property of non-object in C:\wamp64\www\final-project\classes\Image.php on line 25
Call Stack
#   Time    Memory  Function    Location
1   0.0009  381752  {main}( )   ...\my-account.php:0
2   0.0175  439648  Image::uploadImage( )   ...\my-account.php:33

./类/ Image.php：

<?php
class Image {

        public static function uploadImage($formname, $query, $params) {
                $image = base64_encode(file_get_contents($_FILES[$formname]['tmp_name']));

                $options = array('http'=>array(
                        'method'=>"POST",
                        'header'=>"Authorization: Bearer a5d4b7d7eb41f3c2049e1212c628996839cc3066\n".
                        "Content-Type: application/x-www-form-urlencoded",
                        'content'=>$image
                ));

                $context = stream_context_create($options);

                $imgurURL = "https://api.imgur.com/3/image";

                if ($_FILES[$formname]['size'] > 10240000) {
                        die('Image too big, must be 10MB or less!');
                }

                $response = file_get_contents($imgurURL, false, $context);
                $response = json_decode($response);

                $preparams = array($formname=>$response->data->link);

                $params = $preparams + $params;

                DB::query($query, $params);

        }

}
?>

这是给用户的php页面，因此他可以将他的个人资料图片上传到数据库。

if (Login::isLoggedIn()) {
        $userid = Login::isLoggedIn();
} else {
        die('Not logged in!');
}

if (isset($_POST['uploadprofileimg'])) {

        Image::uploadImage('profileimg', "UPDATE users SET profileimg = :profileimg WHERE id=:userid", array(':userid'=>$userid));
        Image();
}
?>

我正在使用php将图像上传到databse sql

0 个答案: