所以我一直在为逃生室拼图做一个arduino项目。它基本上是一个带有液晶屏幕上的计时器的炸弹。在解决了炸弹的所有元素之后,计时器停止并且液晶屏幕显示炸弹已被消除,并为该组提供下一个谜题的线索。 10次中有9次完美运行。但每隔一段时间,当它应该显示炸弹被解散时,液晶屏幕就会显示随机破碎的字符。我没有运气诊断这个问题。希望有人在这里可能会有一个想法。
#include <Keypad.h>
#include <LiquidCrystal.h>
#include <Tone.h>
#define pound 14
Tone tone1;
int Scount = 0;
int Mcount = 0;
int Hcount = 1;
int DefuseTimer = 0;
long secMillis = 0;
long interval = 1000;
char password[6] = "594432";
int currentLength = 0;
int i = 0;
char entered[6];
int ledPin = 23;
int ledPin2 = 25;
int ledPin3 = 27;
int ledPin4 = 29;
int ledPin5 = 31;
int ledPin6 = 34;
const int plugin1 = 44;
const int plugin2 = 46;
const int plugin3 = 48;
const int plugin4 = 50;
const int plugin5 = 52;
int plugin1State = 0;
int plugin2State = 0;
int plugin3State = 0;
int plugin4State = 0;
int plugin5State = 0;
const int switch1 = 37;
int switch1State = 0;
const int key1 = 40;
int key1State = 0;
int puzzle1 = 0;
int puzzle2 = 0;
int puzzle3 = 0;
int solved = 0;
LiquidCrystal lcd(7, 8, 10, 11, 12, 13);
const byte ROWS = 4;
const byte COLS = 3;
char keys[ROWS][COLS] = {
{'1', '2', '3'},
{'4', '5', '6'},
{'7', '8', '9'},
{'*', '0', '#'}
};
byte rowPins[ROWS] = {A0, A1, A2, A3};
byte colPins[COLS] = {A4, A5, A6};
Keypad keypad = Keypad( makeKeymap(keys), rowPins, colPins, ROWS, COLS );
void setup() {
pinMode(ledPin, OUTPUT);
pinMode(ledPin2, OUTPUT);
pinMode(ledPin3, OUTPUT);
pinMode(ledPin4, OUTPUT);
pinMode(ledPin5, OUTPUT);
pinMode(ledPin6, OUTPUT);
pinMode(plugin1, INPUT);
pinMode(plugin2, INPUT);
pinMode(plugin3, INPUT);
pinMode(plugin4, INPUT);
pinMode(plugin5, INPUT);
digitalWrite(plugin1, HIGH);
digitalWrite(plugin2, HIGH);
digitalWrite(plugin3, HIGH);
digitalWrite(plugin4, HIGH);
digitalWrite(plugin5, HIGH);
pinMode(switch1, INPUT);
digitalWrite(switch1, HIGH);
pinMode(key1, INPUT_PULLUP);
digitalWrite(key1, HIGH);
tone1.begin(9);
lcd.begin(16, 2);
Serial.begin(9600);
lcd.clear();
lcd.setCursor(0, 0);
tone1.play(NOTE_E6, 200);
delay(3000);
lcd.clear();
currentLength = 0;
}
void loop()
{
timer();
plugin1State = digitalRead(plugin1);
plugin2State = digitalRead(plugin2);
plugin3State = digitalRead(plugin3);
plugin4State = digitalRead(plugin4);
plugin5State = digitalRead(plugin5);
if (plugin1State == LOW && plugin2State == LOW && plugin3State == LOW && plugin4State == LOW && plugin5State == LOW)
{
puzzle1 = 1;
}
if (puzzle1 == 1)
{
digitalWrite(ledPin4, HIGH);
switch1State = digitalRead(switch1);
if (switch1State == LOW)
{
puzzle2 = 1;
}
}
if (puzzle2 == 1)
{
digitalWrite(ledPin5, HIGH);
key1State = digitalRead(key1);
if (key1State == LOW)
{
puzzle3 = 1;
}
if (key1State == HIGH)
{
digitalWrite(ledPin6, LOW);
}
}
if (puzzle3 == 1)
{
digitalWrite(ledPin6, HIGH);
lcd.clear();
lcd.setCursor(0, 0);
lcd.print("Code: ");
while (currentLength < 6)
{
timer();
char key2 = keypad.getKey();
if (key2 == "#")
{
currentLength = 0;
lcd.clear();
lcd.setCursor(0, 0);
lcd.print("Code: ");
}
else if (key2 != NO_KEY)
{
lcd.setCursor(currentLength + 7, 0);
lcd.cursor();
lcd.print(key2);
entered[currentLength] = key2;
currentLength++;
tone1.play(NOTE_C6, 200);
delay(100);
lcd.noCursor();
lcd.setCursor(currentLength + 6, 0);
lcd.print("*");
lcd.setCursor(currentLength + 7, 0);
lcd.cursor();
}
}
if (currentLength == 6)
{
if (entered[0] == password[0] && entered[1] == password[1] && entered[2] == password[2] && entered[3] == password[3] && entered[4] == password[4] && entered[5] == password[5])
{
solved = 1;
while (solved == 1)
{
lcd.noCursor();
lcd.clear();
lcd.home();
lcd.print("BOMB 1 DEFUSED");
currentLength = 0;
digitalWrite(ledPin3, HIGH);
delay(1500);
lcd.noCursor();
lcd.clear();
lcd.home();
lcd.print("RELEASE");
delay(1500);
lcd.noCursor();
lcd.clear();
lcd.home();
lcd.print("TOXIC GAS");
delay(1500);
lcd.noCursor();
lcd.clear();
lcd.home();
lcd.print("CLUE: %&@$#");
delay(6000);
}
}
else
{
lcd.noCursor();
lcd.clear();
lcd.home();
lcd.print("Wrong Password!");
delay(1500);
currentLength = 0;
}
}
}
}
void timer()
{
if (Hcount <= 0)
{
if ( Mcount < 0 )
{
lcd.noCursor();
lcd.clear();
lcd.home();
lcd.print("The Bomb Has ");
lcd.setCursor (0, 1);
lcd.print("Exploded!");
while (Mcount < 0)
{
digitalWrite(ledPin, HIGH); // sets the LED on
tone1.play(NOTE_A2, 90);
delay(100);
digitalWrite(ledPin, LOW); // sets the LED off
tone1.play(NOTE_A2, 90);
delay(100);
digitalWrite(ledPin2, HIGH); // sets the LED on
tone1.play(NOTE_A2, 90);
delay(100);
digitalWrite(ledPin2, LOW); // sets the LED off
tone1.play(NOTE_A2, 90);
delay(100);
digitalWrite(ledPin3, HIGH); // sets the LED on
tone1.play(NOTE_A2, 90);
delay(100);
digitalWrite(ledPin3, LOW); // sets the LED off
tone1.play(NOTE_A2, 90);
delay(100);
}
}
}
lcd.setCursor (0, 1); // sets cursor to 2nd line
lcd.print ("Timer:");
if (Hcount >= 10)
{
lcd.setCursor (7, 1);
lcd.print (Hcount);
}
if (Hcount < 10)
{
lcd.setCursor (7, 1);
lcd.write ("0");
lcd.setCursor (8, 1);
lcd.print (Hcount);
}
lcd.print (":");
if (Mcount >= 10)
{
lcd.setCursor (10, 1);
lcd.print (Mcount);
}
if (Mcount < 10)
{
lcd.setCursor (10, 1);
lcd.write ("0");
lcd.setCursor (11, 1);
lcd.print (Mcount);
}
lcd.print (":");
if (Scount >= 10)
{
lcd.setCursor (13, 1);
lcd.print (Scount);
}
if (Scount < 10)
{
lcd.setCursor (13, 1);
lcd.write ("0");
lcd.setCursor (14, 1);
lcd.print (Scount);
}
if (Hcount < 0)
{
Hcount = 0;
}
if (Mcount < 0)
{
Hcount --;
Mcount = 59;
}
if (Scount < 1) // if 60 do this operation
{
Mcount --; // add 1 to Mcount
Scount = 59; // reset Scount
}
if (Scount > 0) // do this oper. 59 times
{
unsigned long currentMillis = millis();
if (currentMillis - secMillis > interval)
{
tone1.play(NOTE_G5, 200);
secMillis = currentMillis;
Scount --; // add 1 to Scount
digitalWrite(ledPin2, HIGH); // sets the LED on
delay(10); // waits for a second
digitalWrite(ledPin2, LOW); // sets the LED off
delay(10); // waits for a second
//lcd.clear();
}
}
}
答案 0 :(得分:0)
这很可能与您的LCD电路有关。像你这样的简单代码(不试图以任何方式侮辱你)的事实可以实现9/10次,这意味着代码可能没有任何问题(我没见过)。
要快速检查,请尝试重新安装IDE。这可能会更新使用IDE下载的Arduino库。我怀疑它会解决这个问题,但这是一个快速免费的简单方法来尝试
我会个人建议断开一切,并重新连接它们。如果它不起作用,那么返回那个液晶显示器,让自己换一个新的。
答案 1 :(得分:0)
当我使用非屏蔽的1米带状电缆连接16x2 LCD时,我遇到了同样的问题。带有MCU的主板必须远离显示器放置。它显示出任何电磁干扰的随机特性。例如,打开荧光灯管,启动电动螺丝刀,继电器开关等。缩短ribon电缆解决了这个问题。 无论如何,LCD对电磁干扰很敏感。远离这些来源。