Question

我创建了一个带按钮的GUI。单击按钮时，将打开QDialog框并提示您打开或关闭。当用户选择其中一个选项时，我需要在QWidget中定义的按钮来改变颜色。我知道如何在初始点击时更改颜色，但我需要根据QDialog框选择它。

这是按钮：

self.brkr1_A = QtWidgets.QPushButton(self.centralwidget)
self.brkr1_A.setGeometry(QtCore.QRect(120, 70, 40, 40))
font = QtGui.QFont()
font.setFamily("Times New Roman")
self.brkr1_A.setFont(font)
self.brkr1_A.setStyleSheet("background-color: red;")
self.brkr1_A.setObjectName("brkr1_A")
############ Button Event ##############
self.brkr1_A.clicked.connect(self.clickA1)
########################################

这是按钮事件调用的内容，位于MainWindow：

def clickA1(self):
    if not hasattr(self, 'dialogA1'):
        self.dialogA1= WindowA1(self)
    self.dialogA1.show()
    print("A1 Clicked")

这是提示用户打开或关闭的QDialog：

class WindowA1(QDialog):
    def __init__(self, *args, **kwargs):
        QWidget.__init__(self, *args, **kwargs)
        self.label = QLabel("Ace 1", self)
        self.label.setSizePolicy(QSizePolicy.Expanding, QSizePolicy.Expanding)
        self.button = QPushButton("Open", self)
        self.button2 = QPushButton("Close", self)
        self.layout = QGridLayout()
        self.layout.addWidget(self.label, 0, 0)
        self.layout.addWidget(self.button, 0, 1)
        self.layout.addWidget(self.button2, 1, 1)    
        self.setWindowModality(QtCore.Qt.ApplicationModal)
        self.setWindowTitle("Power Lab 4.0")
        self.setLayout(self.layout)
        self.show()
        ################# Button Events #################
        self.button.clicked.connect(self.OpenBreakerA1)
        self.button2.clicked.connect(self.CloseBreakerA1)
        ######################################################
        # OpenBreaker is where you will communicate with arduino
    def OpenBreakerA1(self):
        print('Opening A1')
    def CloseBreakerA1(self):
        print('Closing A1')

这就是GUI的样子，如果我附上所有代码，你们会讨厌我： brkr1_A is breaker 1 on Ace

根据QDialog选项更改QWidget按钮的颜色？

0 个答案: