Question

我在桌子上有这些数据

SIP DATE LOGIN LOGOUT
237 2017-10-31 10:24:51 10:41:35
611 2017-10-31 10:45:32 10:45:40
258 2017-10-31 10:46:03 12:01:57

这是我的记录集，

我想计算SIP在系统上注册的时间。州R =注册U =未注册但我没有定期登录和注销

我想要：

<meta name="apple-mobile-web-app-capable" content="yes">

并计算保持连接的总时间

感谢您献给我的时间

Answer 1

以下解决方案将起作用：

select sip,
     min(time) as login,
    (case when max(time)=min(time) then 'lost'
          else max(time)
     end
    ) as logout
  from SIPregistration 
where time between '10:00:00' and '11:00:00' 
  and state in('R','U') 
group by sip;

如果THEN没有退出，您可以将sip之后的文字放在您要显示的内容上。

Click here for the DEMO

Answer 2

您希望结果重叠您的范围。

首先创建SIP范围：

 SELECT s1.sip,
        s1.time as login
        s2.time as logout
        COALESCE(s2.time, NOW()) as not_null_logout
 FROM SIPregistration s1
 LEFT JOIN SIPregistration s2  -- I assume there are some SIP without logout
   ON s1.soip =s2.sip
  AND s1.time > s2.time
 -- WHERE s2.time IS NOT NULL  -- optional

现在发现SIP范围是否与您的时间窗口重叠

SELECT s1.sip,
       s1.time as login
       s2.time as logout       
FROM SIPregistration s1
LEFT JOIN SIPregistration s2
  ON s1.soip =s2.sip
 AND s1.time > s2.time
WHERE s1.time < '11:00:00' 
  AND s2.time > '10:00:00' -- sip without logout wont show becasue s2.time is NULL.

Answer 3

最终查询应如下所示：

SELECT sip, `date`
min(time) as login, 
IF(max(time) != min(time), max(time), 'Not Logged Yet In This Range') as logout,
IF(max(time) != min(time), TIMEDIFF(max(time), min(time)), 'Not Logged Yet In This Range') as connected
From words
WHERE time between '10:00:00' and '11:00:00' 
GROUP BY sip;

您可以使用所需内容更改if子句中的文本。我们只检查在where子句

中特定范围内的最大时间是否等于min

IF(expression ,expr_true, expr_false);
DATEDIFF(interval, date1, date2); the interval not required

行mysql的结果

3 个答案: