更新:
关于控制台stringify的问题是重复的;所以我用异步将我的问题改为另一个,因为是sam ecode
我有一个异步函数,通过sequelize orm获取记录,为什么
我的问题是
const genericResolver = async ( table, action , values ) => {
resultValues = {};
let resultValues = await models[table].findById(values.id).then( function (data) {
console.log(' ************** data');
console.log(data);
return data;
}).then( function (data2) {
console.log(' ************** data 2');
console.log(data2);
}
);
console.log('------ resultValues');
console.log(resultValues );
process.exit(1);
for data and data2 I get:
tour {
dataValues:
{ id: 'd61802ff-3eec-4a72-97ca-832f51b96bf0',
name: 'Chipre 2018',
price: '1400.00',
createdAt: 2017-09-05T04:01:27.642Z,
updatedAt: 2017-10-31T11:29:39.484Z },
_previousDataValues:
{ id: 'd61802ff-3eec-4a72-97ca-832f51b96bf0',
name: 'Chipre 2018',
price: '1400.00',
createdAt: 2017-09-05T04:01:27.642Z,
updatedAt: 2017-10-31T11:29:39.484Z },
_changed: {},
_modelOptions:
{ timestamps: true,
validate: {},
freezeTableName: true,
underscored: false,
underscoredAll: false,
paranoid: false,
rejectOnEmpty: false,
whereCollection: { id: 'd61802ff-3eec-4a72-97ca-832f51b96bf0' },
schema: null,
schemaDelimiter: '',
defaultScope: {},
scopes: [],
hooks: {},
indexes: [],
name: { plural: 'tour', singular: 'tour' },
omitNull: false,
sequelize:
Sequelize {
options: [Object],
config: [Object],
dialect: [Object],
queryInterface: [Object],
models: [Object],
modelManager: [Object],
connectionManager: [Object],
importCache: {},
test: [Object] },
uniqueKeys: {} },
_options:
{ isNewRecord: false,
_schema: null,
_schemaDelimiter: '',
raw: true,
attributes:
[ 'id',
'name',
'price',
'seatsmax',
'createdAt',
'updatedAt' ] },
__eagerlyLoadedAssociations: [],
isNewRecord: false }
但对于'resultValues'我得到:
undefined
我正在做异步吗?我正在使用node8所以理论上我不需要将所有内容转换为ES5?只是进口或出口?我怀疑babel正在创建ES6代码
这是我的package.json
{
"name": "myproj",
"version": "1.0.0",
"description": "GraphQL server",
"main": "server.js",
"scripts": {
"start": "nodemon ./server.js --exec babel-node -e js",
"test": "eslint . --ext .js --ext .jsx --ignore-path .gitignore --cache"
},
"author": "",
"license": "MIT",
"devDependencies": {
"babel-cli": "^6.24.0",
"babel-eslint": "^8.0.0",
"babel-preset-es2015": "^6.24.0",
"babel-preset-stage-0": "^6.22.0",
"eslint": "^4.7.1",
"eslint-plugin-react": "^7.3.0",
"nodemon": "^1.11.0"
},
"dependencies": {
"bcrypt-nodejs": "0.0.3",
"body-parser": "^1.17.1",
"cors": "^2.8.3",
"dotenv": "^4.0.0",
"express": "^4.15.2",
"graphql": "^0.9.1",
"graphql-server-express": "^0.6.0",
"graphql-tools": "^0.10.1",
"jsonwebtoken": "^7.2.1",
"lodash": "^4.17.4",
"passport": "^0.4.0",
"passport-jwt": "^3.0.0",
"pg": "^7.2.0",
"sequelize": "",
"validator": "^6.2.0"
}
}
答案 0 :(得分:2)
这是因为对象在JS中作为引用传递,因此当您执行console.log(o)
时,您将在控制台中看到实际值(而不是在调用console.log
时传递给它的值)。
使用JSON.stringify
时,您正在记录字符串,它是按值传递的。所以基本上当你使用JSON时,你会在调用console.log
时看到值。
修改强>
关于您的新问题,问题是您没有从第二个data2
回调中返回then
。使用async/await
时,您根本不需要使用then
:
const data = await models[table].findById(values.id);
或者,如果您愿意,只需返回data2
即可在resultValues
中看到相同的结果:
let resultValues = await models[table].findById(values.id).then(data => {
console.log(' ************** data');
console.log(data);
return data;
}).then(data2 => {
console.log(' ************** data 2');
console.log(data2);
return data2; // <== return here
});
console.log('------ resultValues');
console.log(resultValues );