Question

假设我们在类z中有变量A，它存储两个数字的加法，而变量w在类B中存储两个数字的减法，我们创建派生类D - 我们是否可以将z和w中存储的这些值带到派生类D，以便我们可以将这些数字相乘？

代码看起来像这样：

#include <iostream>

using namespace std;

class c1
{
    int x, y;

public:
    void getdata1(int a, int b)
    {
        x = a;
        y = b;
    }

    void add1()
    {
        int z = x + y;
        cout << "the sum is " << z << endl;
    }
};

class c2
{
    int x, y;

public:
    void getdata2(int a, int b)
    {
        x = a;
        y = b;
    }

    void sub1()
    {
        int w = x - y;
        cout << "the sum is " << w << endl;
    }

};

class D: public c1, public c2
{
/////////////////////////////////////////////////////////////////////////////////////
public:
    void display()
    {
        cout << "the product is s" << z + w; // something like this
    }
};
///////////////////////////////////////////////////////////////////////////////////////

int main()
{
    D obj1;

    obj1.getdata1(10, 5);
    obj1.getdata2(10, 5);
    obj1.add1();
    obj1.sub1();
    obj1.display();

    return 0;
}

Answer 1

您可能需要以下内容：

#include <iostream>

class c1
{
    int x,y;
public:
    c1(int a, int b) : x(a), y(b) {}

    int sum() const { return x + y; }
};

class c2
{
    int x,y;
public:
    c2(int a, int b) : x(a), y(b) {}

    int sub() const { return x - y; }
};

class D: public c1, public c2
{
public:
    D(int a, int b) : c1(a, b), c2(a, b) {}

    int foo() const { return sum() * sub(); }
};

int main(){
    D obj(10, 5);

    std::cout << "the sum is " << obj.sum() << std::endl;
    std::cout << "the sub is " << obj.sub() << std::endl;
    std::cout << "the product is " << obj.foo() << std::endl;
}

Answer 2

首先尝试处理问题的格式化，这里我假设您需要代码来增加这两个变量（z和w）。

#include using namespace std;
 int x,y,z,w;
class c1{
    int x,y;
public:void getdata1(int a, int b){
        x=a;
        y=b;
    }
    void add1()
    {
        int z=x+y;
        cout<<"the sum is "<<z<<endl;
        return z ;
    }
}

class c2 {
 int x,y;
public:void getdata2(int a, int b){
        x=a;
        y=b;
    }
    void sub1()
    {
        int w=x-y;
        cout<<"the sum is "<<w<<endl;
        return w ;
    }

}
class D: public c1,public c2
{
public:void multiply(int a, int b)
{
     cout<<"the multiplication is "<<z*w<<endl;
}
public static int main(){

    D obj1;
    obj1.getdata1(10,5);
    obj1.getdata2(10,5);
    int a = obj1.add1();
    int b = obj1.sub1();
    obj1.display();
    obj1.multiply(a,b)
    return 0;
}

希望这是你期待的解决方案。

我们可以在继承中从基类到派生类获得结果

2 个答案: