Question

我有以下两个数组：

array_Two = [colorZero:"black", colorOne:"red", colorTwo:"green", colorThree:"blue", colorFour:"purple", colorFive:"golden");

array_one = ["colorOne", "colorTwo", "colorThree"];

想要这个带有final array =＆gt;

的o / p

FinalArray = [colorOne:"red",colorTwo:"green",colorThree:"blue"]

我该怎么做？我不知道任何人请知道然后请让我知道。

Answer 1

假设第一个对象提供是一个包含键的对象，您可以使用reduce方法。

array_Two = {colorZero:"black", colorOne:"red", colorTwo:"green", colorThree:"blue", colorFour:"purple", colorFive:"golden"};

array_one = ["colorOne", "colorTwo", "colorThree"];

let final = array_one.reduce(function(acc,elem){
  acc[elem] = array_Two[elem];
  return acc;
},{});
console.log(final);

Answer 2

使用对象，您可以Object.assign并使用spread syntax ...映射单个对象。

var object = { colorZero: "black", colorOne: "red", colorTwo: "green", colorThree: "blue", colorFour: "purple", colorFive: "golden" },
    array = ["colorOne", "colorTwo", "colorThree"],
    result = Object.assign(...array.map(k => ({ [k]: object[k] })));

console.log(result);

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Answer 3

这样的东西？

var array_Two = {colorZero:"black", colorOne:"red", colorTwo:"green", colorThree:"blue", colorFour:"purple", colorFive:"golden"};

var array_one = ["colorOne", "colorTwo", "colorThree"];

var output = {}

array_one.forEach((item) => output[item] = array_Two[item]);

Answer 4

看起来这就是你要找的东西：

array_Two = {colorZero:"black", colorOne:"red", colorTwo:"green", colorThree:"blue", colorFour:"purple", colorFive:"golden"};

array_one = ["colorOne", "colorTwo", "colorThree"];

array_one.forEach(element => {
console.log(array_Two[element])
})

在这种情况下，我使用了箭头函数语法，这是一个ES6功能。此外，您应该使用array_Two的大括号

如何将一个数组中的值与另一个数组中的键进行比较？

4 个答案: