Question

使用SQL Server，我有一个Partial Class SkeduleringDatabasisDataSet End Class Namespace Skedulering.SkeduleringDatabasisDataSetTableAdapters Partial Public Class ParsreelsTableAdapter End Class End Namespace列的表，其数据类型为CreatedAt。我正在尝试编写一个查询，该查询将返回每个日期的总记录，但也会将日期分为一天中的时间，即上午，下午和晚上。所以，例如，下表

datetime

将返回以下结果

ID     createdAt
------------------------------
1      2017-10-17 21:31:52.160
2      2017-10-17 12:12:12.160
3      2017-10-17 09:09:09.160
4      2017-10-17 21:31:52.160
5      2017-10-16 21:31:52.160

我有以下两个查询按日对数据进行分组，然后拆分从日期中提取时间，但我无法弄清楚如何将它们组合在一起。

DayCounter    SessionDay    Morning    Afternoon    Evening
4             2017-10-17    1          1            2
1             2017-10-16    0          0            1

和

SELECT 
    COUNT(createdAt) AS counter, 
    CONVERT(DATE, createdAt) AS sessionDay
FROM 
    MyTable
GROUP BY 
    CONVERT(DATE, createdAt)

Answer 1

您似乎想要条件聚合，以及更清晰地使用日期/时间函数：

select cast(createdAt as date),
       sum(case when datepart(hour, createdat) < 12 then 1 else 0 end) as Morning,
       sum(case when datepart(hour, createdat) >= 12 and datepart(hour, createdat) < 17 then 1 else 0 end) as Afternoon,
       sum(case when datepart(hour, createdat) >= 17 then 1 else 0 end) as Evening
from mytable
group by cast(createdAt as date)
order by cast(createdAt as date);

Answer 2

您正走在正确的解决方案之上。只需将您的查询与sum：

结合起来

SELECT count(createdAt) AS counter, convert(date, createdAt) AS sessionDay
    ,sum(CASE WHEN CAST( CONVERT(CHAR(2), createdAt, 108) AS INT) <12 THEN 1 ELSE 0 end ) as 'Morninig'
    ,sum(case WHEN CAST( CONVERT(CHAR(2), createdAt, 108) AS INT) <17 AND CAST( CONVERT(CHAR(2), createdAt, 108) AS INT) >=12 THEN 1 ELSE 0 end) as 'Afternoon'
    ,sum(case when CAST( CONVERT(CHAR(2), createdAt, 108) AS INT) >=17 THEN 1 ELSE 0 end) as 'Evening'
FROM MyTable
GROUP BY convert(date, createdAt)

结果：

counter sessionDay  Morning     Afternoon   Evening
1       2017-10-16  0           0           1
4       2017-10-17  1           1           2

结果SQL Fiddle

注意：在sql server中使用datepart()以获得更好的查询

Answer 3

请尝试在第一个查询中替换：

CONVERT(DATE, createdAt) AS sessionDay

这一个：

CONVERT(CHAR(10), createdAt, 103) AS sessionDay

并在第二，替换：

CAST(CONVERT(CHAR(2), createdAt, 108) AS INT) < 12

通过

CAST(CONVERT(CHAR(2), createdAt, 108) AS INT)  in 0 to 11

和

WHEN CAST(CONVERT(CHAR(2), createdAt, 108) AS INT) < 17

通过

WHEN CAST(CONVERT(CHAR(2), createdAt, 108) AS INT) in 12 to 16

希望这可以提供帮助

SQL Server组按日期和时间

3 个答案: