Question

我试图创建一个简单的表单，允许我对现有的＆＃39;结果进行新的搜索。页面使用简单的形式。

从另一个（登陆）页面执行搜索时，完全相同的代码可以正常工作。但是，当我尝试将其插入到结果页面中时，我正在

undefined method 'vtype' for #
<Venue::ActiveRecord_Relation:0x007fd6860eb730>

vtype既是表格列，也是传递给搜索的参数名称。

simple_form如下所示：

<%= simple_form_for :results, html: { class: "form-inline justify-content-center" } do |f| %>
    <%= f.error_notification %>
    <%= f.select :vtype, options_for_select([['Happy Hours Anywhere','Anywhere'],['After Work Drinks','After Work Drinks'],['Somewhere to Relax with Friends', 'Relaxing with Friends'], ['A Club Night','Club Night'], ['Somewhere for Date Night','Date Night'], ['A Place to Watch Sports', 'Watching Sports']]),{} ,:class => "form-control select-box font-lightweight"  %>
     starting
    <%= f.select :date, options_for_select(dates_for_search_select.each_with_index.map{|d, i| [d[1],d[0]]}), {}, :class => "form-control select-box font-lightweight" %>
     at
    <%= f.select :time, options_for_select(times_for_search_select.each_with_index.map{|d, i| [d[1],d[0]]}), {}, :class => "form-control select-box font-lightweight" %>
 </h4>

    <%= f.button :submit, 'Discover', :class => 'btn btn-block btn-danger btn-embossed top-margin ' %>
    <%end%>

我的控制器看起来像这样：

def results

    if params.has_key?(:results)

    #@results = Venue.joins(:offers).where("offers.offertype = '2-4-1'")

    @finddate = (params[:results][:date]).to_date
    @findtime = (params[:results][:time]).to_time
    @resultsdate = DateTime.new(@finddate.year,@finddate.month,@finddate.day,@findtime.hour)
    @results = Venue.joins(:offers).where(["venues.vtype = ? and offers.start >= ?", params[:results][:vtype], @resultsdate])

    else

    @results = Venue.joins(:offers).where(["offers.start = ?", Date.today])

    end

  end

这个表单在＆＃39;结果＆＃39;上运行有什么问题？网页？

使用Simple_Form进行搜索 - 未定义的方法

0 个答案: