Question

我有一个这样的数组：

var objectFromArray = [
{ responsibilityName: "test1" },
{ responsibilityName: "test2" },
{ responsibilityName: "test3" },
{ responsibilityName: "test4"}
]

我想从这个数组中创建一个新对象，它们应该具有相同的键。期望的结果应该是这样的：

    public function upload_file_folder(){
       $folder_name = $this->input->post('account_name');  
       if(!is_dir("uploads/gallery/".$folder_name ."/")) {
           mkdir("uploads/gallery/".$folder_name ."/");
       }

       $target_dir = "uploads/gallery/".$folder_name ."/";
       $target_file = $target_dir.$_FILES['gallery']['name'];

       move_uploaded_file($_FILES['gallery']['tmp_name'],$target_file);
   }

这怎么可能在js？

Answer 1

循环遍历数组并使用map或forEach等返回新对象。

＆＃13;

var array = ['test1', 'test2', 'test3', 'test4']
var arr = array.map(value => {
    return {responsibilityName: value};
    
})
console.log(arr);

＆＃13;

Answer 2

迭代数组，在另一个数组中创建对象。就这么简单。

var array = ['test1', 'test2', 'test3', 'test4']
var objectFromArray = []
array.forEach((v)=>{objectFromArray.push({"responsibilityname":v})})

Answer 3

使用 array.map 并将值分配给对象

<强>样本

＆＃13;

var array = ['test1', 'test2', 'test3', 'test4'];

var result = array.map(function(el) {
    var obj = {};
    obj['responsibilityname'] = el;
   
  return obj;
})

console.log(array);
console.log(result);

＆＃13;

Answer 4

根据您的评论调整：您可以使用reduce和map展平对象数组中的数组。

[根据您的评论修改]

const arr = [
  { responsabilityName: ['test1', 'test2', 'test3', 'test4'],
    somethingElse: [1, 2, 3, 4] } ];

const arrMapped = arr
  .reduce( (mappedArr, obj) => 
      Object.keys(obj)
        .map( key => obj[key].map( prop => ({ [key]: prop }) ) )
        .reduce( (p, n) => p.concat(n), [] ), 
   [] );

console.log(arrMapped);

使用类似的键从数组创建对象

4 个答案: