使用MySQL在一个查询中获取相关视频（按标签）和按顺序排序

Question

我有以下表格：

tag
id | name
1  | funny
2  | stack
3  | music

video
id | title         | thumbnail     | video
1  | first video   | thumb.png     | video1.mp4
2  | second video  | thumbnail.png | anothervideo.mp4
3  | third video   | woooow.png    | plssomeonehelpme.mp4

video_tag
id | id_video | id_tag
1  | 1        | 1
2  | 1        | 2
3  | 2        | 2
4  | 3        | 3

video_view
id | date                | id_video
1  | 2017-10-27 23:28:34 | 2
2  | 2017-10-27 23:38:04 | 2
3  | 2017-10-27 00:38:04 | 1
4  | 2017-10-28 10:38:04 | 1
5  | 2017-10-28 12:29:47 | 1
6  | 2017-10-30 15:39:33 | 3
7  | 2017-10-30 17:27:39 | 3
8  | 2017-10-30 00:22:54 | 2

我希望获得相关视频（具有更多相互标签，并按相互标签的数量排序），并获取视频的数量和按视图排序（如果具有相同的相互标签号，按次数排序。）

所以，我尝试过（假设我正在观看的视频id是1）：

SELECT v.title, v.thumbnail, v.video, COUNT(v_t2.id) AS mutualTags 
FROM video_tag v_t 
INNER JOIN video_tag v_t2 ON v_t.id_tag = v_t2.id_tag 
INNER JOIN video v ON v_t2.id_video = v.id 
WHERE v_t.id_video = 1 AND v_t2.id_video != 1 
GROUP BY v_t2.id_tag 
ORDER BY mutualTags DESC

上面的代码返回错误的相互标记，我试图获取视图：

SELECT v.title, v.thumbnail, v.video, COUNT(v_t2.id) AS mutualTags, COUNT(v_v.id) AS views 
FROM video_tag v_t 
INNER JOIN video_tag v_t2 ON v_t.id_tag = v_t2.id_tag 
INNER JOIN video v ON v_t2.id_video = v.id 
INNER JOIN video_view v_v ON v_v.id_video = v_t2.id_video 
WHERE v_t.id_video = 1 AND v_t2.id_video != 1 
GROUP BY v_t2.id_tag, v_v.id_video 
ORDER BY mutualTags DESC, views DESC

但是我得到了错误的相互标记和观点编号......那么，我该怎么做呢？

提前致谢。