Question

在我的代码中，我创建了操作函数，因为它们将在整个代码中多次使用。但是，当我尝试在if语句中调用函数时，程序就会退出。这是相关代码的一部分：

def sendEmail():
emailReceiver = input("Who will receive the email?\n")
emailServer.login("xxxxxxx", "xxxxxx") #logs in 
with provided email and password

emergency = input("What is your emergency?\nTry to include a description of what has happened, names of people involved, and the location.\n")
msg = MIMEMultipart('alternative')   #sets up the email so it has correct formatting
msg['Subject'] = "Emergency Alert"
msg['From'] = "Emergency Alert"
msg['To'] = emailReceiver
textBody = emergency

part1 = MIMEText(textBody, 'plain') #makes sure the email is in text format 
rather than HTML
msg.attach(part1)

emailServer.sendmail("xxxxxxx", emailReceiver, msg.as_string())
print("Alert sent.")

def sendSMS():
message = input("what would you like to send? ".as_string())
client.api.account.messages.create(
to = "xxxxxxxx",
from_ = "xxxxxxxx",
body = message)

def makeCall():
makeCall = client.api.account.calls.create(
to = "xxxxxxxx",
from_ = "xxxxxxxx",
url = "xxxxxxxx") 

ask = input(" Choose option:\n 1. Send SMS\n 2. Send email\n 3.Make phone call\n 4. Send SMS and email\n 5. Send SMS and make call\n 6. Send Email and make call")

if ask == 1 :
    print(sendSMS())
    print("SMS sent.")

if ask == 2 :
    print(sendEmail())

即使函数在if语句中调用时实际上不起作用，但当它们不属于if语句时，它们会在调用时按预期工作。我确定我在某个地方犯了一个愚蠢的错误，但我似乎无法找到它。任何帮助是极大的赞赏。谢谢。

Answer 1

问题是输入返回一个字符串并将其与int类型变量进行比较，因此永远不会调用您的函数：

if ask == '1' :
    print(sendSMS())
    print("SMS sent.")

if ask == '2' :
    print(sendEmail())

为什么我的功能没有被正确调用？

1 个答案: