某些代码行不会执行

时间:2017-10-30 20:03:23

标签: c++ string getline

我的程序内容对于这个问题无关紧要,但我们几乎都在使用类和对象来保存信息。我的代码如下:

#include <iostream>
using namespace std;

class Car
{
private:
    int carNumber;
    bool loaded;
    string reportingMark, kind, destination;
public:
    void setUp(string reportingMark, int carNumber, string kind, bool 
loaded, string destination);
    void output();
};

void input(string &reportingMark, int &carNumber, string &kind, bool 
&loaded, string &destination);

/* ******************** main ********************
 */
int main()
{
    Car *ptr;

    string reportingMark, kind, destination;
    int carNumber;
    bool loaded;

    Car c = *new Car();
    ptr = &c;
    input(reportingMark, carNumber, kind, loaded, destination);
    ptr->setUp(reportingMark, carNumber, kind, loaded, destination);
    ptr->output();
    return 0;
}
/* ******************** Member Functions ********************
 */

/* ******************** setUp ********************
 Takes 5 parameters by value: reporting mark, car number, kind, loaded, 
and destination
 Inputs these paramaters into the Car class' variables
 */
void Car::setUp(string rm, int cn, string k, bool l, string d)
{
    reportingMark = rm, carNumber = cn, kind = k, loaded = l, 
destination = d;
}

/* ******************** output ********************
 Prints the reporting mark, car number, kind, loaded, and destination 
in a neat format
 */
void Car::output()
{
    cout << "\n\nReporting Mark: " << reportingMark << "\nCar Number: " 
<< carNumber << "\nKind: " << kind << "\nCar is loaded: " << loaded << 
"\Destination: " << destination << endl;
}
/* ******************** Global Functions ********************
 */

/* ******************** input ********************
 Takes the reporting mark, car number, kind, loaded, and destination as 
reference parameters
 Asks the user to input these values
 */
void input(string &reportingMark, int &carNumber, string &kind, bool 
&loaded, string &destination)
{
    do
    {
        cout << "What is the Reporting Mark? (Between 2-4 characters) ";
        getline(cin, reportingMark);
    if(reportingMark.length() < 2 || reportingMark.length() > 4) cout << "invalid input, try again\n";
} while(reportingMark.length() < 2 || reportingMark.length() > 4);
cout << "What is the Car Number? ";
cin >> carNumber;
int carNumResponse;

do
{
    cout << "What is the Kind? (Choose '1' for business, '2' for maintenance, or '3' for other) ";
    cin >> carNumResponse;
    if(carNumResponse < 1 || carNumResponse > 3) cout << "invalid input, try again\n";
} while(carNumResponse < 1 || carNumResponse > 3);
if(carNumResponse == 1) kind = "business";
if(carNumResponse == 2) kind = "maintenance";
if(carNumResponse == 3) kind = "other";

int loadedResponse;

do
{
    cout << "Is the car loaded? (Type '1' if true and '2' if false) ";
    cin >> loadedResponse;
    if(loadedResponse < 1 || loadedResponse > 2) cout << "invalid input, try again\n";
} while(loadedResponse < 1 || loadedResponse > 2);
if(loadedResponse == 1) loaded = true;
if(loadedResponse == 2) loaded = false;

cout << "What is the Destination? ";
getline(cin, destination);
}

我的计划的最后两行:

cout << "What is the Destination? ";
getline(cin, destination);

不让我因某种原因输入任何内容。我错误地使用了getline吗?它在程序的其他部分使用相同的方式。感谢任何有帮助的人!

1 个答案:

答案 0 :(得分:0)

这里的问题是您在执行cin>>操作之前有getlinecin>>所做的是它从流中提取所有字符,但留下了新行字符。

对于getline,默认分隔符是换行符。因此它会跳过输入,因为它会收到流中留下的换行符。

解决方案,您必须执行cin.ignore (),这将刷新流,即删除换行符。我建议您在使用cin.ignore ()功能之前执行getline()

属性: 发帖帮助:How to use cin.getline in blocking mode