Question

我在控制器中有以下内容：

outputmodel.Add(new SP_RESULTS.RS_Plans()
{
  id = Convert.ToDecimal(SPOutput["id"]),
  name = Convert.ToString(SPOutput["name"]),
  code = Convert.ToString(SPOutput["code"]),
  from = Convert.ToDateTime(SPOutput["from"]),
  to = Convert.ToDateTime(SPOutput["to"]),
  days = Convert.ToDecimal(SPOutput["days"]),
  type_id = convert.YoString(SPOutput["type_id"]),
  package = Convert.ToString(SPOutput["package"]),
  day = Convert.ToDecimal(SPOutput["day"]),
  charge = SPOutput["charge"] as decimal?,
  type = Convert.ToString(SPOutput["type"]),
  percentage= SPOutput["percentage"] as decimal?,
  taxes = Convert.ToDecimal(SPOutput["taxes"]),
  order = Convert.ToDecimal(SPOutput["order"]),
  level = SPOutput["level"] as decimal?,
  Column15 = Convert.ToDecimal(SPOutput[15]),
  type_order = (SPOutput["type_order"]) as decimal?,
  adults = SPOutput["adults"] as decimal?,
});

var order = outputmodel.OrderBy(c => c.from);
ViewData["RS_Output"] = order;

从MS SQL存储过程中获取输出并存储在viewdata中（按FROM日期排序）。

我的HTML有以下行开始构建表

@foreach (var item in ViewData["RS_Output"] as Enumerable<app.Models.SP_RESULTS.RS_Plans>)
{
//basic <tr> <td> </td> </tr> table setup, using @item.variablename to pull info from the viewdata.
}

我想要实现的输出是针对CODE下的每个TYPE，其中from date =＆gt;当前日期，列出房间类型/包裹名称等。

我得到的输出是

我想要得到的是

我认为我需要的是现在的foreach之后的一个foreach，但我不能为我的生活在脑海中找到它。我改变了

我的控制器中的var order行现在读

var order = outputmodel.OrderBy(c => c.rate);

..我把HTML表创建代码放在if循环中

@foreach (var item in ViewData["RS_Output"] as Enumerable<app.Models.SP_RESULTS.RS_Plans>)
{
if (item.to >= DateTime.now)
{
//basic <tr> <td> </td> </tr> table setup, using @item.variablename to pull info from the viewdata.
}
}

..但是，正如我所说，我很难过。

我想我需要在新创建的if循环中使用另一个foreach，但我无法弄清楚如何。

@foreach (var item in ViewData["RS_Output"] as Enumerable<app.Models.SP_RESULTS.RS_Plans>)
{
if (item.to >= DateTime.now)
{
//other table headers/data

     <tr>
         <td>
             @item.type
         </td>
     </tr>
     <tr>
        <td>
            Room Type
        </td>
        <td>
            Package / Service
        </td>
        <td>
            Availablility
        </td>
        <td>
            Charge
        </td>
        <td>
            PAX
        </td>
        <td>
            Level
        </td>
     </tr>
     <tr>
  ==>     @foreach (subitem = item.type)
  ==>        {
  ==>        foreach (item.type)
  ==>        {
        <td>
            @item.type_id
        </td>
        <td>
            @item.package 
        </td>
        <td>
            @item.Column15
        </td>
        <td>
            @item.charge
        </td>
        <td>
           @item.adults
        </td>
        <td>
            @item.level
        </td>
  ==>           }
  ==>           }
     </tr>


}
}

有人可以提出建议吗？

感谢

UPDATE：

嗨，我找到的工作是，如果我创建一个名为string previous_type =“”的变量，另一个名为decimal previous_id = 0，那么，在视图中，我可以修改

if (item.to >= item.checkdate)
  {
  if ((previous_id != item.id) && (previous_type != item.type.ToString()) )
    {
     //some more code
  if (item.type.ToString().Equals(previous_type) == false)
  {
      previous_type = item.type.ToString();
      previous_date_from = item.date_from;
   }
    //etc
   }

感谢大家的帮助

Answer 1

好的，我想你想要的是先对数据进行分组，然后显示一个表格，然后显示＆＃39;子表格＆＃39;对于每个类型的住宿？

如果是这样，那么是的，你可以用嵌套的foreach循环来做到这一点，但你仍然可以更好地强烈地输入你的视图并在控制器中进行分组（或者在某种服务层中可能更好）它可以更容易测试/重复使用）...但是为了让你开始，像这样：

型号：

//Raw data
public class DataRowModel
{
    public int Id { get; set; }
    public string Class{ get;set;}
    public string Description { get; set; }
    public DateTime BookingDate { get; set; }
}

//Grouped data
public class GroupedDataRowModel
{
    public string Class { get; set; }
    public IEnumerable<DataRowModel> Rows { get; set; }
}

//View model
public class DataRowsViewModel
{
    public IEnumerable<GroupedDataRowModel> Results { get; set; }
}

控制器操作：

public ActionResult TestData()
{
    var PretendDatabaseCall = new List<DataRowModel>
    {
        new DataRowModel{
            Id =1,
            BookingDate =new DateTime(2017,1,1),
            Description ="Booking 1",
            Class="Room"
        },
        new DataRowModel{
            Id =2,
            BookingDate =new DateTime(2017,2,1),
            Description ="Booking 2",
            Class="Room"
        },
        new DataRowModel{
            Id =3,
            BookingDate =new DateTime(2017,3,1),
            Description ="Booking 3",
            Class="Suite"
        },
        new DataRowModel{
            Id =4,
            BookingDate =new DateTime(2017,4,1),
            Description ="Booking 4",
            Class="Room"
        },
    };

    //We can now get the data from the database.  We want to group by class so we can
    //get a summary of items by class rather than a big flat list.  Most LINQ to SQL implementations
    //(e.g. Entity Framework) when working with Raw entities could convert this to SQL so the SQL server
    //does the grouping, but if not it can happen in memory (get all records, then standard LINQ does it on
    //the complete list)
    var dataGroupedByClass = PretendDatabaseCall
        //Minor Edit: apply filtering here not in the view!
        .Where(x=>x.BookingDate >= Datetime.Now)
        //Group by class.
        .GroupBy(x => x.Class)
        //for each class, get the records.
        .Select(grpItem => new GroupedDataRowModel()
        {
            //'key' is the thing grouped by (class)
            Class = grpItem.Key,
            //grpItem has all the rows within it accessible still.
            Rows = grpItem.Select(thisRow => thisRow)
        });

    var model = new DataRowsViewModel
    {
        Results = dataGroupedByClass
    };

    return View("~/Views/Home/TestData.cshtml", model);

}

观看：

@* Strongly typed view.  saves any casting back and forth.*@
@model SimpleWeb.Models.DataRowsViewModel
@{
    ViewBag.Title = "TestData";
}

<h2>TestData</h2>


<table>

    <thead></thead>
    <tbody>
        @foreach (var groupEntry in Model.Results)
        {
            @*Add single row with just the class...*@
            <tr><td>@groupEntry.Class</td></tr>
            @*Header row for each class of booking*@
            <tr>
                <td>Id</td>
                <td>Description</td>
                <td>Date</td>
            </tr>
            foreach (var row in groupEntry.Rows)
            {
                @*add new row for each actual row*@
                <tr>
                    <td>
                        @row.Id
                    </td>
                    <td>
                        @row.Description
                    </td>
                    <td>
                        @row.BookingDate
                    </td>
                </tr>
            }
        }

    </tbody>

</table>

这会生成我想要的数据：

Room
Id  Description Date
1   Booking 1   01/01/2017 00:00:00
2   Booking 2   01/02/2017 00:00:00
4   Booking 4   01/04/2017 00:00:00
Suite
Id  Description Date
3   Booking 3   01/03/2017 00:00:00

显然你想要的房间＆＃39;和＆＃39;套房＆＃39;部分包含更多信息，但这有望帮助您入门？

在MVC中的FOREACH中的FOREACH

UPDATE：

1 个答案: