SELECT distinct AD.ReferenceNumber, AD.ProjectTitle, Z.ZoneCode, C.CompanyName,SS.AssignedTo, ZG.ZoneGroupName,au.Amount
FROM ApplicationDetails AD
LEFT JOIN ApplicationFormsDetails AS b ON (AD.referencenumber = b.referencenumber)
LEFT JOIN ScheduleSummaries AS SS ON (AD.ReferenceNumber = SS.ReferenceNo)
INNER JOIN AppTypes as at on ss.ItemCode = at.Category
INNER JOIN Companies AS C ON (AD.CompanyId = C.CompanyID)
INNER JOIN Zones Z ON (C.ZoneCode = Z.ZoneCode)
INNER JOIN ZoneGroups ZG ON (Z.ZoneGroup = ZG.ZoneGroupId)
LEFT JOIN AssessmentUsedItems au on ah.AssessmentHeaderId = au.HeaderId
WHERE AD.ApplicationDate BETWEEN '2017-10-01' AND '2017-10-31' AND ZG.ZoneGroupCode = 'HO' and ah.referencenumber = 'N-101317-A1-02'
GROUP BY AD.ReferenceNumber, AD.ProjectTitle, Z.ZoneCode, C.CompanyName,SS.AssignedTo, ZG.ZoneGroupName,au.Amount--, ah.ApplicationForm,au.Amount
此查询的输出是重复每个AssignTO的数量。
输出:
答案 0 :(得分:0)
也许你想尝试使用SUM(ISNULL(au.amount, 0)) AS amount
代替au.amount
,并从au.amount
移除GROUP BY
......
答案 1 :(得分:0)
尝试此查询:
SELECT AD.ReferenceNumber,
AD.ProjectTitle,
Z.ZoneCode,
C.CompanyName,
SS.AssignedTo,
ZG.ZoneGroupName,
SUM(COALESCE(au.Amount,0)) AS Amount
FROM ApplicationDetails AD
LEFT JOIN ApplicationFormsDetails AS b
ON (AD.referencenumber = b.referencenumber)
LEFT JOIN ScheduleSummaries AS SS
ON (AD.ReferenceNumber = SS.ReferenceNo)
INNER JOIN AppTypes AS at
ON ss.ItemCode = at.Category
INNER JOIN Companies AS C
ON (AD.CompanyId = C.CompanyID)
INNER JOIN Zones Z
ON (C.ZoneCode = Z.ZoneCode)
INNER JOIN ZoneGroups ZG
ON (Z.ZoneGroup = ZG.ZoneGroupId)
LEFT JOIN AssessmentUsedItems au
ON ah.AssessmentHeaderId = au.HeaderId
WHERE AD.ApplicationDate BETWEEN '2017-10-01' AND '2017-10-31'
AND ZG.ZoneGroupCode = 'HO'
AND ah.referencenumber = 'N-101317-A1-02'
GROUP BY
AD.ReferenceNumber,
AD.ProjectTitle,
Z.ZoneCode,
C.CompanyName,
SS.AssignedTo,
ZG.ZoneGroupName