Question

我将来自TCP行的数据作为词典列表。但有时我会一次收到两个数据包。他们看起来像

sdk

我想将其转换为： -

[{"property1":"value1", "property2":"value2"}, {"property1":"value1", "property2":"value2"}][{"property1":"value1", "property2":"value2"}][{"property1":"value1", "property2":"value2"}, {"property1":"value1", "property2":"value2"}]

Answer 1

您可以分两步完成：

将][替换为,，因为这些连续的方括号代表单独的数据包，加入它们的最简单方法是用逗号替换
将字符串转换为包含ast.literal_eval的字典，即“安全”eval。

import ast
ast.literal_eval(string.replace('][', ','))

[{'property1': 'value1', 'property2': 'value2'},
 {'property1': 'value1', 'property2': 'value2'},
 {'property1': 'value1', 'property2': 'value2'},
 {'property1': 'value1', 'property2': 'value2'},
 {'property1': 'value1', 'property2': 'value2'}]

这里假设您将这些“数据包”作为字符串接收。

Answer 2

输入

l='[{"property1":"value1", "property2":"value2"}, {"property1":"value1", "property2":"value2"}][{"property1":"value1", "property2":"value2"}][{"property1":"value1", "property2":"value2"}, {"property1":"value1", "property2":"value2"}]'

使用re

import re
re.findall("\[?([^\]]+)?\]", l)

输出

['{"property1":"value1", "property2":"value2"}, {"property1":"value1", "property2":"value2"}',
 '{"property1":"value1", "property2":"value2"}', 
 '{"property1":"value1", "property2":"value2"}, {"property1":"value1", "property2":"value2"}'
]

修复格式错误的字符串？

2 个答案: