Question

我是角度js的新手，我现在正在练习过滤器。我完全能够遍历对象数组但是当我使用对象的对象时，我的浏览器会抛出错误：＆＃34;未捕获的SyntaxError：意外的令牌＆＃34;

<!DOCTYPE>
<html>
    <head>
    </head>
    <body>
        <div ng-app="myApp">
            <div ng-controller="myCont">

                <div ng-repeat="b in ar2">
                    {{b}}
                </div>

                {{a}}
                </br></br>
                {{c | myFilt}}
                </br>
                </br>
                <div ng-repeat="(key,value) in d">
                    {{key.a|myFilt}}
                </div>
            </div>
        </div>
        <script src="jquery-3.0.0.js"></script>
        <script src="angular.js"></script>
        <script src="angular_try.js"></script>

    </body>
</html>

这是角度js：

var myApp = angular.module("myApp",[])

myApp.controller("myCont",["$scope","$filter",function($scope,$filter){
$scope.a ="pro";
$scope.arr = ["abc","bcd","cdb"];
$scope.arr3 = [100,200,300];
$scope.ar2=[];
$scope.c = 10;
$scope.d = {{a:"mishtu",b:500,c:"mondal"},{a:"tulu",b:400,c:"mondal"},
{a:"titlu",b:600,"c":"mondal"}}
}])

Answer 1

对象包含始终在（键，值）对中的值，但对象包含

$scope.d = {{a:"mishtu",b:500,c:"mondal"},{a:"tulu",b:400,c:"mondal"},
{a:"titlu",b:600,"c":"mondal"}}

正在保存对象列表，因此您应该将其声明为数组。喜欢这个

$scope.d = [{a:"mishtu",b:500,c:"mondal"},{a:"tulu",b:400,c:"mondal"},
{a:"titlu",b:600,"c":"mondal"}]

应该如何使用：

＆＃13;

var app = angular.module('myApp', []);
app.controller('MyController', ['$scope', function($scope) {
  $scope.title = 'Hello world';

  $scope.d = [{
    a: "mishtu",
    b: 500,
    c: "mondal"
  }, {
    a: "tulu",
    b: 400,
    c: "mondal"
  }, {
    a: "titlu",
    b: 600,
    "c": "mondal"
  }];

}]);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-controller='MyController' ng-app="myApp">
  <div>{{title}}</div>

  <table border="1" ng-repeat="myObj in d">
    <tr ng-repeat="(x, y) in myObj">
      <td>{{x}}</td>
      <td>{{y}}</td>
    </tr>
  </table>
</div>

＆＃13;

在角度js中使用ng-repeat over object literal时出错

1 个答案: