Question

我正在尝试链接两个firebase帐户，通常用户将使用社交媒体或电子邮件或anonmus帐户登录，然后用户将使用电话登录。我需要链接这两个帐户。

父视图

将调用父视图中的某个功能以注册电话号码

class welcomeView: UIViewController, FUIAuthDelegate {

 //stores current user
 var previosUser = FIRUser()


 override func viewDidLoad() {
    super.viewDidLoad()
  if let user = Auth.auth().currentUser {
        previosUser = user 
    }else{
        Auth.auth().signInAnonymously() { (user, error) in

            if error != nil {
                //handle error
            }
            previosUser = user!
        }
    }

 }






 func signUpWithPhone(){ 
    let vc = signUpWithPhoneView()
    vc.authUI?.delegate = self
    vc.auth?.languageCode = "ar"
    self.present(vc, animated: true) 

  }


}

子视图中的

（signUpWithPhoneView）我提出了FUIPhoneAuth

phoneProvider.signIn(withPresenting: self)

子视图

import UIKit
import FirebaseAuthUI
import FirebasePhoneAuthUI

class signUpWithPhoneView: UIViewController {

 fileprivate(set) var authUI = FUIAuth.defaultAuthUI()
 var didload = false

 override func viewDidLoad() {
    super.viewDidLoad()
 }


 override func viewWillAppear(_ animated: Bool) {
    if !didload { // stops from looping 
        didload = !didload

        guard let authUI = self.authUI else {return}
        let phoneProvider = FUIPhoneAuth.init(authUI: authUI)
        self.authUI?.providers = [phoneProvider] 
     >> phoneProvider.signIn(withPresenting: self)

    }
 }


}

当用户登录时，子视图将自动被解除，并且我具有将在父视图中调用的didSignInWith函数。我需要关联以前的用户帐户和用户电话帐户

父视图

    func authUI(_ authUI: FUIAuth, didSignInWith user: FirebaseAuth.User?, error: Error?) {

    if let user = user{

        // link the the two accounts

    }else{

    }

}

我尝试使用

进行链接

        let provider = PhoneAuthProvider.provider(auth: authUI.auth!)
        let credential = PhoneAuthProvider.credential(provider)


        previosUser.link(with: credential, completion: { (user, error) in
            if error != nil {
                print("this is linking two acounts error : " , error)
            }
        })

但凭据中存在错误

...previosUser.link(with: *credential*, completion: ...

中的

Cannot convert value of type '(String, String) -> PhoneAuthCredential' to expected 
argument type 'AuthCredential'

任何帮助将不胜感激谢谢

Answer 1

您正在使用authUI.auth获取提供程序，然后不使用它来获取凭据，并且您当前正在使用实例方法credential的静态引用。

实例方法本身需要两个字符串并返回AuthCredential，这就是您看到(String, String) -> AuthCredential的原因。您必须使用必须从用户收集的验证ID和代码创建凭证。

guard let auth = authUI.auth else { return }

let provider = PhoneAuthProvider.provider(auth: auth)
let credential = provider.credential(
   withVerificationID: "XXXXXXXXXXXX", 
   verificationCode: "XXXXXX"
)

// ...

iOS链接两个firebase帐户

1 个答案: