Question

我整个上午都在谷歌搜索这个，并尝试各种修复，但我无法弄明白。

当我尝试运行时，我不断收到错误“TypeError：req.user.findOneAndUpdate不是函数”：

req.user.findOneAndUpdate({_id: req.user._id}, { $addToSet: { flashcards : { $each: cards }}}, {upsert : true}, function(err, doc) {
        if(err) return console.log(err);
        res.send(doc);
    });

我已经尝试将req.user明确地转换为用户模型（例如var newUser = new User（req.body），尝试简化查询等但似乎没有任何工作。

编辑：使用模型声明

const User = require('../models/user');

var NewUser = new User(req.user);

    NewUser.findOneAndUpdate({_id: req.user._id}, { $addToSet: { flashcards : { $each: cards }}}, {upsert : true}, function(err, doc) {
        if(err) { return console.log(err); }
        else { return res.send(doc);}
    });

用户模型架构

const mongoose = require('mongoose'),
    Schema = mongoose.Schema,
    FlashcardSchema = require('./flashcardSchema'),
    bcrypt = require('bcrypt-nodejs');

var UserSchema = new Schema({
    username: {
        type: String,
        required: false
      },
      email: {
        type: String,
        required: true,
        unique: true
      },
      password: {
        type: String
      },
      created_on: {
        type: Date,
        default: Date.now
      },
        points: Number,
        flashcards: [FlashcardSchema],
        courses: [{type: Schema.Types.ObjectId, ref: 'Course'}]
});

UserSchema.methods.generateHash = function(password) {
    return bcrypt.hashSync(password, bcrypt.genSaltSync(8), null);
};

UserSchema.methods.validPassword = function(password) {
    return bcrypt.compareSync(password, this.password);
};

module.exports = UserSchema;

和模型

const mongoose = require('mongoose'),
    Schema = mongoose.Schema,
    UserSchema = require('../schemas/userSchema');

module.exports = mongoose.model('User', UserSchema);

Answer 1

解决方案是在模型上运行函数，而不是在它的实例上运行。所以而不是：

var NewUser = new User(req.user);
NewUser.findOneAndUpdate...

执行：

User.findOneAndUpdate...

Answer 2

检查错误后你回来了所以

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  var count = 1;
  var total = 13;

  $('.fa-caret-right').on('click' ,function scrollHorizontal() {
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      var scrollTo = $("#p"+count);
      var where = $(scrollTo).offset().left - 150;

      $('#counter').html(number);

      $(".gallery").stop().css("transform","translateX(-"+where+"px)");
    }
 );

});

findOneAndUpdate不是一个函数

2 个答案: