mongoose嵌套填充3/4级后的自引用模型

Question

总是发现3级后猫鼬没有填充。 尝试使用mongoose@^4.12.4

＆＃13;

＆＃13;

var mongoose = require('mongoose');
var config = require('./config')
var Promise = require('bluebird')
mongoose.Promise = Promise
mongoose.connect(config.dbURL, config.mongo.options)
var NodeSchema = new mongoose.Schema({
  friend: {
    type: mongoose.Schema.Types.ObjectId,
    ref: 'Node'
  },
  name: String
});
var autoPopulateChildren = function(next) {
  this.populate('friend');
  next();
};
NodeSchema
  .pre('findOne', autoPopulateChildren)
  .pre('find', autoPopulateChildren)
var Node = mongoose.model('Node', NodeSchema)
var user1 = new Node({
  name: 'A'
})
var user2 = new Node({
  name: 'B'
})
var user3 = new Node({
  name: 'C'
})
var user4 = new Node({
  name: 'D'
})
var user5 = new Node({
  name: 'E'
})
user1.friend = user2._id
user2.friend = user3._id
user3.friend = user4._id
user4.friend = user5._id

Node.remove({})
  .then(Promise.all([user5, user4, user3, user2, user1].map(p => p.save())))
  .then(_ => Node.findOne({
    name: 'A'
  }))
  .then(r => console.log(r))

＆＃13;

＆＃13;

＆＃13;

得到了以下.. 的 A - ＆GT;乙 - ＆GT; C - ＆GT;对象

但预计以下...... 的 A - ＆GT;乙 - ＆GT; C - ＆GT; d - ＆GT，E

请帮忙！.. 提前谢谢..

Answer 1

你可以试试这个吗？希望它能起作用

user1.friend = user2
user2.friend = user3
user3.friend = user4
user4.friend = user5

Node.remove({})
  .then(Promise.all([user5.save(), user4.save(), user3.save(), user2.save(), user1.save()]))
  .then(() => Node.findOne({
      name: 'A'
   }))
  .then(r => console.log(r))