Question

与cuda 3.5兼容的旧源代码与较新的cuda版本不兼容，例如7.5。例如，

cuda_runtime_api.cc: In function ‘cudaError_t cudaMemcpyToSymbol(const char*, const void*, size_t, size_t, cudaMemcpyKind)’:
cuda_runtime_api.cc:556:141: error: declaration of C function ‘cudaError_t cudaMemcpyToSymbol(const char*, const void*, size_t, size_t, cudaMemcpyKind)’ conflicts with
__host__ cudaError_t CUDARTAPI cudaMemcpyToSymbol(const char *symbol, const void *src, size_t count, size_t offset, enum cudaMemcpyKind kind)
                                                                                                                                         ^
In file included from cuda_runtime_api.cc:155:0:
/usr/local/cuda/include/cuda_runtime_api.h:4335:39: error: previous declaration ‘cudaError_t cudaMemcpyToSymbol(const void*, const void*, size_t, size_t, cudaMemcpyKind)’ here
 extern __host__ cudaError_t CUDARTAPI cudaMemcpyToSymbol(const void *symbol, const void *src, size_t count, size_t offset __dv(0), enum cudaMemcpyKind kind __dv(cudaMemcpyHostToDevice));

所以，这表示代码中的cudaMemcpyToSymbol（）与7.5实现不兼容。源代码是

__host__ cudaError_t CUDARTAPI cudaMemcpyToSymbol(const char *symbol, const void *src, size_t count, size_t offset, enum cudaMemcpyKind kind)
{....}

和/usr/local/cuda/include/cuda_runtime_api.h上的7.5版

extern __host__ cudaError_t CUDARTAPI cudaMemcpyToSymbol(const void *symbol, const void *src, size_t count, size_t offset __dv(0), enum cudaMemcpyKind kind __dv(cudaMemcpyHostToDevice));

我该如何解决？

更新：错误文件中的cuda_runtime_api.cc指向用户定义的可用here。

mahmood@u1604:~/gem5-gpu/benchmarks/libcuda$ g++ -std=c++0x -O3 -g -Wall -fPIC  -DCUDART_VERSION=7050 -I./ -I/usr/local/cuda/include -I../../gem5/util/m5 -c cuda_runtime_api.cc -o cuda_runtime_api.o
cuda_runtime_api.cc: In function ‘cudaError_t cudaMemcpyToSymbol(const char*, const void*, size_t, size_t, cudaMemcpyKind)’:
cuda_runtime_api.cc:556:143: error: declaration of C function ‘cudaError_t cudaMemcpyToSymbol(const char*, const void*, size_t, size_t, cudaMemcpyKind)’ conflicts with
 __host__ cudaError_t CUDARTAPI cudaMemcpyToSymbol(const char *symbol, const void *src, size_t count, size_t offset , enum cudaMemcpyKind kind )
                                                                                                                                            ^
 In file included from cuda_runtime_api.cc:155:0:
/usr/local/cuda/include/cuda_runtime_api.h:4335:39: error: previous declaration ‘cudaError_t cudaMemcpyToSymbol(const void*, const void*, size_t, size_t, cudaMemcpyKind)’ here
 extern __host__ cudaError_t CUDARTAPI cudaMemcpyToSymbol(const void *symbol, const void *src, size_t count, size_t offset __dv(0), enum cudaMemcpyKind kind __dv(cudaMemcpyHostToDevice));
                                   ^

Answer 1

在评论之后，必须传递符号本身，而不是字符串中的名称。以下是有关如何使用此新API签名的示例示例：

#include "cuda_runtime.h"
#include "device_launch_parameters.h"

#include <stdio.h>

__constant__ int a[1];

__global__ void kernel()
{
    printf("a = %d\n", a[0]);
}

int main()
{
    int value = 42;
    cudaMemcpyToSymbol(a, &value, sizeof(int));
    kernel << <1, 1 >> > ();
    return cudaDeviceSynchronize();
}

应打印

a = 42

将旧的cuda代码移植到7.5

1 个答案: