Question

只是尝试查询数据库以从Web UI更新行（及其中的数据）。我有一张桌子＆＃34;客户＆＃34; - 只是想要更新记录（我已经实现了INSERT和DELETE）。

我正在回应该表并包含通过以下语法更新的选项：

<td><a href =Scripts/Update.php?id=".$row['Customer_ID'].">Update</a> </td>";

这显示＆＃34;更新＆＃34;就像我需要的那样，在每一行的末尾，当我点击它时，它会运行更新脚本。大。

虽然回显了表格，但我还将输入类型更改为文本，因此用户可以点击该文档，编辑数据并单击更新按钮。

然而问题是，当我尝试更新表中的记录时，它会刷新回所选的标题页但没有更新任何信息，只返回带有已清除数据单元格的行。（它没有删除数据库中的行，因为我在表中显示了客户ID，但仍然存在）。

我的Update.php脚本如下：

     <?php
    include "../Connection.php";

    $Firstname = mysqli_real_escape_string($con, $_POST['FirstName']);
    $Lastname = mysqli_real_escape_string($con, $_POST['LastName']);
    $CusEmail = mysqli_real_escape_string($con, $_POST['Email']);
    $CusUsername = mysqli_real_escape_string($con, $_POST['Username']);
    $CusPhone = mysqli_real_escape_string($con, $_POST['Phone']);   
    $CusCountry = mysqli_real_escape_string($con, $_POST['Country']);
    $CusTown = mysqli_real_escape_string($con, $_POST['Town']);
    $CusAddress = mysqli_real_escape_string($con, $_POST['Address']);
    $CusPostcode = mysqli_real_escape_string($con, $_POST['Postcode']);

            $sqlupdate = "UPDATE customer SET Customer_FirstName = '$Firstname', Customer_LName ='$Lastname', Customer_Email ='$CusEmail', Customer_Username ='$CusUsername', Customer_Phone ='$CusPhone', Customer_Country ='$CusCountry', Customer_Town ='$CusTown', Customer_Address = '$CusAddress', Customer_Postcode = '$CusPostcode' WHERE Customer_ID ='$GET_[id]'";

mysqli_query($con, $sqlupdate);
mysqli_close($con);

    if($sqlupdate){
        header('Location:../CustomerRecords.php');
        }
        else{
            echo "Failed!";
            }

我尝试了一些事情，例如，我通常使用POST方法从HTML表单执行此操作，而这样我就是通过echo a href ...（这是我第一次））。我在DELETE函数上使用了相同的方法，效果很好。接下来，我通常会添加：

if ($_SERVER["REQUEST_METHOD"] == "POST") {

并且

if(isset($_POST)){

如果需要，但是再试一次，得到相同的结果。

可能是我的SQL语法错了，但我无法弄清楚，如果有人可以建议它会很棒。

谢谢。

更新：

我上面做了一些修改，我现在一直在盯着这段代码，只是＆＃34;玩＆＃34;现在用它...我也试过这个，但它会抛出错误，这看起来比现在更糟糕了：

        $sqlupdate = "UPDATE customer SET Customer_FirstName = '$Firstname', Customer_LName ='$Lastname', Customer_Email ='$CusEmail', Customer_Username ='$CusUsername', Customer_Phone ='$CusPhone', Customer_Country ='$CusCountry', Customer_Town ='$CusTown', Customer_Address = '$CusAddress', Customer_Postcode = '$CusPostcode' WHERE Customer_ID ='$_GET[id]'";


    if(mysqli_query($con, $sqlupdate)){
        header('Location:../CustomerRecords.php');
        }
        else{
            echo "Failed!";
            }

Answer 1

您实际上并未执行查询。后：

$sqlupdate = "UPDATE customer SET Customer_FirstName = '$Firstname', Customer_LName ='$Lastname', Customer_Email ='$CusEmail', Customer_Username ='$CusUsername', Customer_Phone ='$CusPhone', Customer_Country ='$CusCountry', Customer_Town ='$CusTown', Customer_Address = '$CusAddress', Customer_Postcode = '$CusPostcode' WHERE Customer_ID ='$GET[id]'";

您需要添加：

mysqli_query($con,$sqlupdate);

PHP

1 个答案: