Question

我正在尝试在SQL中进行查询。该数据库是IMBD之一。这是形式：

所以，我需要电影“低俗小说”（id = 2175869）的演员/女演员，这部电影从未在其他电影中与另一位与制片小说的演员/女演员共同演出。

应该是这样的：

SELECT person_id FROM cast_info WHERE movie_id = 2175869 AND
person_id NOT IN (SELECT )

但我无法弄明白如何做第二部分。

Answer 1

查询后来用作子查询，返回除了Pulp Fiction以外的电影，其中不止一个Pulp Fiction的演员在其中播放

SELECT movie_id
FROM cast_info
WHERE
    movie_id <> 2175869 AND
    person_id IN (SELECT person_id FROM cast_info WHERE movie_id = 2175869)
GROUP BY movie_id
HAVING COUNT(*) > 1

现在让人们在纸浆小说中扮演从未参加过这样一部电影的人

SELECT person_id
FROM cast_info
WHERE
    movie_id = 2175869 AND
    person_id NOT IN (
        SELECT person_id FROM cast_info WHERE movie_id IN (
            SELECT movie_id
            FROM cast_info
            WHERE
                movie_id <> 2175869 AND
                person_id IN (SELECT person_id FROM cast_info WHERE movie_id = 2175869)
            GROUP BY movie_id
            HAVING COUNT(*) > 1
        )
    )

注意：我假设每部电影只能演一个演员一次。如果同一个演员可以在同一部电影中为不同的角色投放，则将COUNT(*)替换为COUNT(DISTINCT person_id)。

Answer 2

首先，您需要看到纸浆小说中的所有演员：

SELECT person_id  as pulp_actor_id
FROM cast_info
WHERE movie_id = 2175869

然后你需要找到所有演员二人组：

SELECT c1.person_id as actor1_id
       c2.person_id as actor2_id
FROM cast_info c1
JOIN cast_info c2
  ON c1.person_id < c2.person_id
WHERE c1.movie_id = 2175869
  AND c2.movie_id = 2175869;

在纸浆小说旁找到所有二人组合的电影。

SELECT actor1_id, actor2_id, actor1_movies.movie_id
FROM (SELECT c1.person_id as actor1_id
             c2.person_id as actor2_id
      FROM cast_info c1
      JOIN cast_info c2
        ON c1.person_id < c2.person_id
      WHERE c1.movie_id = 2175869
        AND c2.movie_id = 2175869) as duos
JOIN cast_info as actor1_movies
  ON duos.actor1_id = actor1_movies.person_id
 AND actor1.movie_id <> 2175869
LEFT JOIN cast_info actor2_movies
  ON duos.actor2_id = actor2_movies.person_id
 AND actor1_movies.movie_id = actor2_movies.movie_id
WHERE actor2.movie_id IS NOT NULL;

现在让所有来自纸浆小说的演员不在最后的结果中

SELECT person_id as pulp_actor_id
FROM cast_info c
LEFT JOIN ( SELECT actor1_id, actor2_id, actor1_movies.movie_id
            FROM (SELECT c1.person_id as actor1_id
                         c2.person_id as actor2_id
                  FROM cast_info c1
                  JOIN cast_info c2
                    ON c1.person_id < c2.person_id
                  WHERE c1.movie_id = 2175869
                    AND c2.movie_id = 2175869) as duos
            JOIN cast_info as actor1_movies
              ON duos.actor1_id = actor1_movies.person_id
             AND actor1.movie_id <> 2175869
            LEFT JOIN cast_info actor2_movies
              ON duos.actor2_id = actor2_movies.person_id
             AND actor1_movies.movie_id = actor2_movies.movie_id
            WHERE actor2.movie_id IS NOT NULL;
            WHERE movie_id = 2175869 ) as duos
  ON c.person_id IN ( actor1_id, actor2_id )
WHERE duos.movie_id IS NULL

在具有复杂子查询的SQL中练习

2 个答案: