Question

我的Spring版本是5.x而tomcat版本是8.5，所以根据介绍，他们将支持在没有web.xml的情况下运行的web应用程序，但是我收到了404错误，请参阅下面的项目结构：

我使用此网址访问我的应用程序，但得到404错误：
http://localhost:8080/SpringMVC/

请参阅下面的代码：

RootConfig.java：

package spittr.config;

import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.ComponentScan.Filter;
import org.springframework.context.annotation.Configuration;
import org.springframework.context.annotation.FilterType;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;

@Configuration
@ComponentScan(basePackages= {"spitter"},
               excludeFilters= {@Filter(type=FilterType.ANNOTATION, value=EnableWebMvc.class)}
              )
public class RootConfig {

}

WebConfig.java：

package spittr.config;

import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.ViewResolver;
import org.springframework.web.servlet.config.annotation.DefaultServletHandlerConfigurer;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurer;
import org.springframework.web.servlet.view.InternalResourceViewResolver;


@Configuration
@EnableWebMvc
@ComponentScan("spittr.web")
public class WebConfig implements WebMvcConfigurer{

    public ViewResolver viewResolver()
    {
        InternalResourceViewResolver resolver = new InternalResourceViewResolver();
        resolver.setPrefix("/WEB-INF/views/");
        resolver.setSuffix(".jsp");
        resolver.setExposeContextBeansAsAttributes(true);
        return resolver;
    }

    @Override
    public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) 
    {
        configurer.enable();
    }
}

SpittrWebAppInitializer.java：

package spittr.config;

import org.springframework.web.servlet.support.AbstractAnnotationConfigDispatcherServletInitializer;

public class SpittrWebAppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class<?>[] {RootConfig.class}; 
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class<?>[] {WebConfig.class};
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] {"/"};
    }

}

HomeController.java：

package spittr.web;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;

@Controller
public class HomeController {
    @RequestMapping(value="/",method=RequestMethod.GET)
    public String home()
    {
        System.out.println("test");
        return "home";
    }
}

home.jsp：

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>this is the Home Jsp page</title>
</head>
<body>
    <h1>Hello, Spring MVC!</h1>
</body>
</html>

从Eclipse控制台，我可以看到输出＆＃34; test＆＃34;这意味着Spring上下文找到了控制器，但似乎找不到jsp页面，我不知道原因，有人能告诉我代码有什么问题吗？

Answer 1

尝试在@Bean public ViewResolver viewResolver(){}方法之上添加@Bean注释。因此，Spring容器将您的方法管理为bean，您的自定义配置可能会起作用。

package PracticePackage;

public class whileLoop {

    public static void main(String[] args) {

        int i=1;

        System.out.println("Quotient "+i/2);    
        System.out.println("Remainder "+i%2);

    }

}

表示方法生成一个由Spring管理的bean 容器

Spring MVC应用程序有404错误

1 个答案: