我有一张平坦的桌子。我想将其转换为嵌套的json格式。
database schema table_name col_name
exploration dbo TestTable name
exploration dbo TestTable last_name
exploration dbo Table_1 name
exploration dbo Table_1 d_id
exploration dbo tblMonitorChange EventType
exploration dbo tblMonitorChange SchemaName
exploration dbo tblMonitorChange ObjectName
exploration dbo tblMonitorChange ObjectType
exploration dbo tblMonitorChange EventDate
exploration dbo tblMonitorChange SystemUser
exploration dbo tblMonitorChange CurrentUser
exploration dbo tblMonitorChange OriginalUser
ReportServer dbo Users UserID
ReportServer dbo Users Sid
ReportServer dbo Users UserType
ReportServer dbo Users AuthType
ReportServer dbo Users UserName
ReportServer dbo Users ServiceToken
ReportServer dbo Users Setting
我正在寻找一般解决方案,而不是硬编码列名。
任何帮助将不胜感激。
答案 0 :(得分:0)
我递归地解决了这个问题。这个功能测试和工作:
def table_to_json(model):
print('-------------------------------------------------------------')
doc = {};
col_names = list(model.columns)
grouped = model.groupby(col_names[0])[col_names[1]]
values = grouped.apply(lambda x: set(x.tolist()))
a = values.shape
if(len(col_names)==2):
return dict(values)
keys = list(grouped.groups.keys())
for k in keys:
doc.update({k:table_to_json(model[model[col_names[0]] == k][col_names[1:]])})
return doc
它将数据帧(在我的第一篇文章中检查)作为输入,并返回字典文档作为输出。这是输出的一部分:
{'exploration': {'dbo': {'Table_1': {'d_id', 'name'},
'TestTable': {'last_name', 'name'},
'tblMonitorChange': {'CurrentUser',
'EventDate',
'EventType',
'ObjectName',
'ObjectType',
'OriginalUser',
'SchemaName',
'SystemUser'}}},
'ReportServer': {'dbo': {'ActiveSubscriptions': {'ActiveID',
'SubscriptionID',
'TotalFailures',
'TotalNotifications',
'TotalSuccesses'},
'Batch': {'Action',
'AddedOn',
'BatchID',
'BoolParam',
'Content',
'Item',
'Param',
'Parent',
'Properties'}}}}