Question

我实现了django rest框架并收到了以下结果：

{
    "count": 3,
    "next": null,
    "previous": null,
    "results": [
        {
            "id": 2,
            "created_at": "2017-10-16T09:55:07.663791Z",
            "modified_at": "2017-10-16T09:55:07.663846Z",
            "visible": true,
            "name": "Viewer",
            "permissions": [
                2,
                3
            ]
        },
       ...
    ]
}

所以我希望字段权限为：

 "permissions": [
    "name permission 1",
    "name permission 2"
 ]

我该怎么办？

编辑：

我添加了我的模型和序列化代码：

作用：

class Role(BaseModel):
    class Meta:
        db_table = 'role'

    name = models.CharField(max_length=255, null=False)
    module = models.CharField(max_length=30)
    permissions = models.ManyToManyField(Permission,
                                     related_name='role_permission',
                                     through='RolePermission', )


    def __str__(self):
        return self.name

RolePermission：

class RolePermission(models.Model):
    class Meta:
        db_table = 'role_permission'
        unique_together = (('role', 'permission'),)

    role = models.ForeignKey(Role)
    permission = models.ForeignKey(Permission)

RoleSerializer

class RoleSerializer(serializers.ModelSerializer):

    class Meta:
        model = Role
        fields = '__all__'

Answer 1

您可以修改RoleSerializer来实现此目的，以及Permission模型的新序列化程序类。

class PermissionSerializer(serializers.ModelSerializer):
    class Meta(object):
        model = Permission
        fields = ('name', )


class RoleSerializer(serializers.ModelSerializer):
    permissions = PermissionSerializer(many=True)

    class Meta:
        model = Role
        fields = '__all__'

如何自定义相关结果Django Rest Framework

1 个答案: