用Python

Question

我想总结2个dictonaries

inv = {'gold coin': 41, 'rope': 1}
inv2 = {'rope': 3, 'torch': 10}

我用Counter子类

实现了它

inv = Counter({'gold coin': 41, 'rope': 1})
inv2 = Counter({'rope': 3, 'torch':10})
result = dict(inv + inv2)
print(result)

输出：

{'gold coin': 41, 'rope': 4, 'torch': 10}

现在我很好奇是否有可能用循环和其他方式对这2个字典进行求和。

有什么想法吗？

Answer 1

你可以试试这个：

import itertools
inv = {'gold coin': 41, 'rope': 1}
inv2 = {'rope': 3, 'torch': 10}
final_data = [(a, list(b)) for a, b in itertools.groupby(list(inv.items())+list(inv2.items()), key=lambda x:x[0])]
new_final_data = {a:sum(c for i, c in b) for a, b in final_data}

输出：

{'gold coin': 41, 'rope': 4, 'torch': 10}

Answer 2

你可以使用词典理解 -

print({k: inv.get(k, 0) + inv2.get(k, 0) for k in set(inv) | set(inv2) })

打印 - {'gold coin': 41, 'rope': 4, 'torch': 10}

Answer 3

inv = {'gold coin': 41, 'rope': 1}
inv2 = {'rope': 3, 'torch': 10}
result = {val: inv.get(val, 0) + inv2.get(val, 0) for val in set(inv).union(inv2)}
print(result)

输出：

{'torch': 10, 'rope': 4, 'gold coin': 41}

Answer 4

这是一个更长的方法 with loops ，所以你可以根据需要添加任意数量的dicts

inv = {'gold coin': 41, 'rope': 1,}
inv2 = {'rope': 3, 'torch': 10}

def sum_dicts(*args):
    new_dict ={}
    for arg in args:
        for key, value in arg.items():
            if key in new_dict:
                new_dict[key] += value
            else: 
                new_dict[key] = value
    return new_dict

print(sum_dicts(inv, inv2))