我目前正在研究在Node.js上运行时只记录下面对象的每个值的代码,每次迭代延迟一秒并与字符串&#34连接;您现在正在观看"
const episodes = [
{ id: 's06e01', title: 'Pilot' },
{ id: 's06e02', title: 'Top Banana' },
{ id: 's06e03', title: 'Charity Drive' },
{ id: 's06e04', title: 'Visiting Ours' },
{ id: 's06e05', title: 'My Mother, the Car' },
{ id: 's06e06', title: 'In God We Trust' },
{ id: 's06e07', title: 'Storming the castle' },
{ id: 's06e08', title: 'Pier Pressure' },
{ id: 's06e09', title: 'Public Relations' },
];
const finaleEpisode = { id: 's06e10', title: 'Bringing Up Buster' };
const addToPlaylist = episodes.concat(finaleEpisode)
下面是我设法做到这一点,但我知道有一个更简单的方法来做到这一点,我打算使用一个循环,但无法找到一种方法来恢复每次迭代后的控制台日志。因此我使用Asynchronous JS来延迟打印和清除功能
console.log("You are Now Watching " + addToPlaylist[0].id + ' ' + addToPlaylist[0].title);
setTimeout(function(){console.log('\033c'); }, 3000);
setTimeout(function(){console.log("You are Now Watching " + addToPlaylist[1].id + ' ' + addToPlaylist[1].title); }, 4000);
setTimeout(function(){console.log('\033c'); }, 5000);
setTimeout(function(){console.log("You are Now Watching " + addToPlaylist[2].id + ' ' + addToPlaylist[2].title); }, 6000);
setTimeout(function(){console.log('\033c'); }, 7000);
setTimeout(function(){console.log("You are Now Watching " + addToPlaylist[3].id + ' ' + addToPlaylist[3].title); }, 8000);
setTimeout(function(){console.log('\033c'); }, 9000);
setTimeout(function(){console.log("You are Now Watching " + addToPlaylist[4].id + ' ' + addToPlaylist[4].title); }, 10000);
setTimeout(function(){console.log('\033c'); }, 11000);
setTimeout(function(){console.log("You are Now Watching " + addToPlaylist[5].id + ' ' + addToPlaylist[5].title); }, 12000);
setTimeout(function(){console.log('\033c'); }, 13000);
setTimeout(function(){console.log("You are Now Watching " + addToPlaylist[6].id + ' ' + addToPlaylist[6].title); }, 14000);
答案 0 :(得分:1)
function doTask(num, max) {
console.log("do whatever you want with " + num);
if(num < max) {
window.setTimeout(function() {
doTask(++num, max);
}, 2000);
}
}
好的,这是递归的。不要超过几百万。
答案 1 :(得分:0)
我猜你正在寻找这样的东西:
for (let i = 0; i < addToPlaylist.length; i++) {
setTimeout(() => {
// clears all characters printer on previous loop
process.stdout.clearLine();
// use \r at the end to return the cursor to the begining
process.stdout.write("You are Now Watching " + addToPlaylist[i].id + ' ' + addToPlaylist[i].title + "\r");
}, i * 2000);
}
您的解决方案并非真正“恢复”通过console.log
btw打印的行。