Question

这两个SQL选择独立工作，但我需要帮助将它们组合成一个select语句，以生成一个包含两个查询中所有字段的单行。

选择＃1：

select 
    'F' row_type, 
    sum(movement.override_pay_amt_n + tmp.b) as total_amount 
from 
    movement, 
    (select coalesce(sum(driver_extra_pay.amount_n),0.0) b 
     from driver_extra_pay,deduct_code,movement 
     where driver_extra_pay.company_id = 'tms' 
       and driver_extra_pay.movement_id = 1
       and driver_extra_pay.movement_id = movement.id 
       and driver_extra_pay.payee_id = movement.override_payee_id 
       and movement.company_id = 'tms' 
       and code_type = 'E' 
       and deduct_code.id = driver_extra_pay.deduct_code_id 
       and deduct_code.company_id = 'tms') tmp 
where 
    movement.id = 1
    and movement.company_id = 'tms'

选择＃2：

select 
    'BBS' row_type, 
    movement.override_pay_amt, 
    override_pay_amt as total_amount, 
    movement.override_pay_amt_n,
    movement.override_pay_amt_d,
    movement.override_pay_amt_c,
    movement.override_pay_amt_r
from 
    movement 
where 
    movement.id = 1 
    and movement.company_id = 'tms' ;

我的组合选择：

select 
    'BBSALL' row_type, 
    movement.override_pay_amt, 
    override_pay_amt as total_amount, 
    movement.override_pay_amt_n,
    movement.override_pay_amt_d,
    movement.override_pay_amt_c,
    movement.override_pay_amt_r,
    sum(movement.override_pay_amt_n + tmp.b) as total_amount 
from 
    movement, 
    (select coalesce(sum(driver_extra_pay.amount_n),0.0) b 
     from driver_extra_pay,deduct_code,movement 
     where driver_extra_pay.company_id = 'tms' 
       and driver_extra_pay.movement_id = 1
       and driver_extra_pay.movement_id = movement.id 
       and driver_extra_pay.payee_id = movement.override_payee_id 
       and movement.id = 1 
       and movement.company_id = 'tms' 
       and code_type = 'E' 
       and deduct_code.id = driver_extra_pay.deduct_code_id 
       and deduct_code.company_id = 'tms') tmp

但我得到了这个错误......

Msg 8120，Level 16，State 1，Line 48
列＆＃39; movement.override_pay_amt＆＃39;在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

Answer 1

只需添加分组，假设您希望汇总结果。

SELECT  'BBSALL' row_type
,       movement.override_pay_amt
,       override_pay_amt AS total_amount
,       movement.override_pay_amt_n
,       movement.override_pay_amt_d
,       movement.override_pay_amt_c
,       movement.override_pay_amt_r
,       SUM(movement.override_pay_amt_n + tmp.b) AS total_amount
FROM    movement
,       (SELECT COALESCE(SUM(driver_extra_pay.amount_n), 0.0) b
         FROM   driver_extra_pay
         ,      deduct_code
         ,      movement
         WHERE  driver_extra_pay.company_id = 'tms'
                AND driver_extra_pay.movement_id = 1
                AND driver_extra_pay.movement_id = movement.id
                AND driver_extra_pay.payee_id = movement.override_payee_id
                AND movement.id = 1
                AND movement.company_id = 'tms'
                AND code_type = 'E'
                AND deduct_code.id = driver_extra_pay.deduct_code_id
                AND deduct_code.company_id = 'tms'
        ) tmp     
GROUP BY row_type
,       movement.override_pay_amt
,       override_pay_amt
,       movement.override_pay_amt_n
,       movement.override_pay_amt_d
,       movement.override_pay_amt_c
,       movement.override_pay_amt_r

如何组合SQL Server coalesce，sum和子查询以获取单个返回的行

1 个答案: