Question

我有一个国家列表：国家= ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']

我希望得到所有不包含任何国家/地区的行。这是我的代码：

with open('file.txt') as f:
    lines = f.readlines()[1:5]
    a = [line.split(':') for line in lines]
    for country in countries:
        for line in a:
            if country not in line:
                print(line)

print（line）打印所有行，而不是打印那些不包含国家/地区的行

Answer 1

这就是any()和all()函数的用途。

countries = ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']
with open('file.txt') as f:
    lines = f.readlines()[1:5]
    a = [line.split(':') for line in lines]
    for line in a:
        if not any(country in line for country in countries):
            print(line)

Answer 2

你可以试试这个：

data = [i.strip('\n').split(":") for i in open('filename.txt')]
countries = ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']
final_data = [i for i in data if not any(b in countries for b in i)]

Python在列表中获取不在列表中的项目

2 个答案: