如何在通知中显示日期和时间？

Question

当用户完成选择日期和时间并按下按钮时，通知将发送给用户，但如何在通知中显示日期和时间？

我的Firebase数据

$target_dir = "upload/";

if(isset($_POST['CopyImages']))
    foreach ($_POST['photoselect'] as $photourl) {
        $photoname= basename($photourl);
        copy($photourl, $target_dir.'/'.$photoname);
    }
}

这是我存储时间和日期数据的方式：

private void Confirm()  {


    String Doctor = mySpinner.getSelectedItem().toString();
    myRef.child("Appointment").child(userID).child("Doctor").setValue(Doctor);


    NotificationManager nm = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);

    notification.setSmallIcon(R.drawable.ic_stat_name);
    notification.setTicker("This is the ticker");
    notification.setWhen(System.currentTimeMillis());
    notification.setContentTitle("Appointment");
    notification.setContentText("Notification");

    NotificationCompat.InboxStyle inboxStyle = new NotificationCompat.InboxStyle();
    String[] dates = new String[3];
    dates[0] = "Date :" ;
    dates[1] = "Time :" ;
    dates[2] = "Doctor :" + Doctor;
    inboxStyle.setBigContentTitle("Appointment");
    for (String mDate : dates)
    {
        inboxStyle.addLine(mDate);
    }
    notification.setStyle(inboxStyle);

    nm.notify(0,notification.build());

Answer 1

要获取日期和时间，请使用以下代码：

DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference myRef = rootRef.child("Appointment").child(userID);
ValueEventListener eventListener = new ValueEventListener() {
    @Override
    public void onDataChange(DataSnapshot dataSnapshot) {
        String date = ds.child("Date").getValue(String.class);
        String time = ds.child("Time").getValue(String.class);
        //add date and time to notification
        Log.d("TAG", data + " - " + time);
    }

    @Override
    public void onCancelled(DatabaseError databaseError) {}
};
youmyRefrRef.addListenerForSingleValueEvent(eventListener);

你的出局将是：

10/31/2017 - 6:21AM

请记住仅在date方法中使用time和onDataChange()，否则将始终为null，原因是此方法的异步行为。