Question

for i in file:
   file = [i.strip() for i in file]
return [file[i:i+1] for i in range(0, len(file),1)]

输出：

[['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]

这是我的包含子列表的列表。

如何取消' '？所以['1,3,4,5,2'] -> [1,3,4,5,2]

谢谢！（：

Answer 1

你可以试试这个：

s = [['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]
final_data = [map(int, i[0].split(",")) for i in s]

输出：

[[1, 3, 4, 5, 2], [4, 2, 5, 3, 1], [1, 3, 2, 5, 4], [1, 2, 4, 3, 5], [1, 3, 4, 5, 2], [2, 1, 3, 5, 4], [1, 3, 4, 5, 2], [3, 5, 2, 4, 1], [1, 4, 5, 2, 3], [5, 1, 4, 3, 2], [3, 2, 5, 4, 1], [3, 1, 2, 5, 4], [2, 5, 1, 4, 3], [3, 2, 1, 4, 5], [4, 5, 3, 1, 2], [1, 5, 4, 3, 2], [1, 5, 3, 4, 2], [2, 1, 4, 3, 5], [4, 1, 2, 5, 3]]

Answer 2

试试这个：

import ast
l = []
s = [['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]
for li in s:
   l.append(list(ast.literal_eval(li[0])))

注意： ast 是一个内置（标准）模块，如果你不知道它，它带有python安装

Answer 3

一线解决方案：

list_1=[['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]




print([[int(item_3) for item_3 in item_1 if item_3.isdigit()] for item in list_1 for item_1 in item])

输出：

[[1, 3, 4, 5, 2], [4, 2, 5, 3, 1], [1, 3, 2, 5, 4], [1, 2, 4, 3, 5], [1, 3, 4, 5, 2], [2, 1, 3, 5, 4], [1, 3, 4, 5, 2], [3, 5, 2, 4, 1], [1, 4, 5, 2, 3], [5, 1, 4, 3, 2], [3, 2, 5, 4, 1], [3, 1, 2, 5, 4], [2, 5, 1, 4, 3], [3, 2, 1, 4, 5], [4, 5, 3, 1, 2], [1, 5, 4, 3, 2], [1, 5, 3, 4, 2], [2, 1, 4, 3, 5], [4, 1, 2, 5, 3]]

详细说明：

for item in list_1:
    for item_1 in item:
        new=[]
        for item_3 in item_1:
            if item_3.isdigit():
                new.append(int(item_3))
        print(new)

从列表中删除元素。蟒蛇

3 个答案: