Question

我有两个数组。例如：

SELECT date_format(TimeColumn, '%h:%i %p') AS TimeColumn FROM Table ORDER BY TimeColumn ASC

但是，我的firstArray = ["9,54,59,60,66,362,372,399,400,411,428"] secondArray - ["9,40,62,399"] let newArray = firstArray.filter { (string) -> Bool in return secondArray.contains(string)返回4个结果，当只有两个匹配为newArray且40“匹配”62和400时出错。

我发现了这个问题，这让我更接近，但没有解决完全匹配错误。 How to get list of common elements of 2 array in swift由RAJAMOHAN-S回答

如何将其设置为仅获得完全匹配？

更新：有些事情不正确。

根据以下内容，我有以下代码：

但是，以下是打印结果：

            subGroupArrayResult.insert("[", at: subGroupArrayResult.startIndex)
            subGroupArrayResult.insert("]", at: subGroupArrayResult.endIndex)
            arraySpeciesIDResult.insert("[", at: arraySpeciesIDResult.startIndex)
            arraySpeciesIDResult.insert("]", at: arraySpeciesIDResult.endIndex)


            let newArray  = subGroupArrayResult.filter { (string) -> Bool in
                return arraySpeciesIDResult.contains(string)
            }

            print("subGroupArrayResult is \(subGroupArrayResult)")
            print("arraySpeciesIDResult is \(arraySpeciesIDResult)")
            print("new Array is \(newArray)")

Answer 1

我在swift playground中运行了你的确切代码，并使newArray等于一个空数组。这是因为firstArray只包含一个对象String

“9,54,59,60,66,362,372,399,400,411,428”

逗号不会将字符串分解为更小的字符串或整数。引号内的所有字符都是字符串的一部分，包括逗号。

secondArray也只包含一个字符串

“9,40,62,399”

过滤firstArray测试字符串“9,40,62,399”是否包含字符串“9,54,59,60,66,362,372,399,400,411,428”，这是假的，因此newArray为空。

如果在数组的开头和结尾删除引号，则所有数字都是Ints，同样的函数返回newArray只有匹配[9,399]。

对于Int

let firstArray = [9,54,59,60,66,362,372,399,400,411,428]
let secondArray = [9,40,62,399]

let newArray  = firstArray.filter { (string) -> Bool in
    return secondArray.contains(string)
}
// Returns [9, 399]

对于字符串

let firstArray = ["9","54","59","60","66","362","372","399","400","411","428"]
let secondArray = ["9","40","62","399"]

let newArray  = firstArray.filter { (string) -> Bool in
    return secondArray.contains(string)
}
// Returns ["9", "399"]

查找两个数组中的常见精确元素

1 个答案: