Question

我需要你的帮助，我写了这个函数来使用vlc.py保存音频流，但是当我在终端上运行时没有任何反应。当我使用python解释器时，我创建了音频文件。感谢

import vlc

def grabar_audio(stream, parametros):

    radio = stream
    datos = parametros
    instancia = vlc.Instance()
    player = instancia.media_player_new()
    media = instancia.media_new(radio, datos)
    media.get_mrl()
    player.set_media(media)
    player.play()

    return media

radio = 'http://212.83.146.67:7212/stream'

datos = "--sout=#standard{access=file,mux=ts,dst='/home/eparionad/Descargas/ProyectoPython/prueba32.mp3'} --run-time=10 --stop-time=10"

grabar_audio(radio, datos)

Answer 1

问题是该实例是在程序运行时执行的，在示例中，您总是使用具有无限循环的GUI，但是对于您的代码，我们必须提供它。

import sys
import vlc
from time import sleep

def grabar_audio(stream, parametros):

    radio = stream
    datos = parametros
    instancia = vlc.Instance()

    player = instancia.media_player_new()
    media = instancia.media_new(radio, datos)
    media.get_mrl()

    player.set_media(media)
    player.play()
    return media

radio = 'http://212.83.146.67:7212/stream'

datos = "--sout=#standard{access=file,mux=ts,dst='/home/eparionad/Descargas/ProyectoPython/prueba32.mp3'} --run-time=10 --stop-time=10"

grabar_audio(radio, datos)
while True:
    try:
        sleep(1)
    except KeyboardInterrupt:
        sys.exit(0)

在python和vlc中保存直播

1 个答案: