Question

我无法将变量作为参数传递给此api：wounderground。

我想使用输入框将输入作为城市和州，并将它们作为变量传递给URI，以便用户可以获得他们的天气预报。但是，我无法将变量作为参数传递给api，并且导致错误的URI（不是URI？）或URI :: InvalidURIError。有人可以告诉我如何解决它并告诉我为什么我会收到此错误。如果您需要更多信息，请告诉我。谢谢！

型号：weathers.rb 班级天气

attr_accessor :temperature, :city, :state, :icon, :weekday_name, 
:chance_of_rain, :chance_of_snow, :uvi, :tomorrow, :tomorrow_condition, 
:tomorrow_icon, :day_one, `enter code here`:day_one_condition, 
:day_one_high, :day_one_low, :day_two, :day_two_condition, 
:day_two_high, :day_two_low

def initialize(city, state)
@city = city
@state = state

week_weather_hash = fetch_week_forecast(city, state)
week_forecast(week_weather_hash)
end

def fetch_week_forecast(city, state)

HTTParty.get("http://api.wunderground.com/api/apikey/forecast10day/q/#
{city}/#{state}.json")
end

def week_forecast(week_weather_hash)
weekly_forecast_response = 
week_weather_hash.parsed_response['response']['forecast']
self.day_one = weekly_forecast_response['txt_forecast']['forecastdays']
['forecastday'][0]['title']
self.day_one_condition = weekly_forecast_response['txt_forecast']
['forecastdays']`enter code here`['forecastday'][0]['fcttext']

self.day_one_high = weekly_forecast_response['simpleforecast']
['forecastdays']['forecastday'][0]['high']['fahrenheit']
self.day_one_low = weekly_forecast_response['simpleforecast']
['forecastdays']['forecastday'][0]['low']['fahrenheit']

self.day_two = weekly_forecast_response['txt_forecast']['forecastdays']
['forecastday'][2]['title']
self.day_two_condition = weekly_forecast_response['txt_forecast']
['forecastdays']`enter code here`['forecastday'][2]['fcttext']

self.day_two_high = weekly_forecast_response['simpleforecast']
['forecastdays']`enter code here`['forecastday'][1]['high']
['fahrenheit']
self.day_two_low = weekly_forecast_response['simpleforecast']
['forecastdays']['forecastday'][1]['low']['fahrenheit']

这是我的控制器：     class ForecastsController＆lt; ApplicationController的
    def show
    @weather = Weathers.new（params [：city]，params [：state]）
    结束
    端

show.html.erb          每周预测：
    ＆lt;％= @ weathers.day_one％＆gt; ：＆lt;％= @ weathers.day_one_condition％＆gt;
    高/低：＆lt;％= @ weathers.day_one_high％＆gt; F：＆lt;％= @ weathers.day_one_low％＆gt; F

<br>
<%=@weathers.day_two %> : <%= @weathers.day_two_condition %>
<br>
High/Low: <%=@weathers.day_two_high %>F : <%=@weathers.day_two_low 
%>F

**我的index.html.erb和新表单**

<%= form_tag("/forecast", method: "get", class: "form-inline") do %> 
<p class = "city-input">
<%= label_tag :City %>
<%= text_field_tag :city,  nil, class: "form-control", placeholder: 
"City Name" %>
</p>

<p class= "state-input">
<%= label_tag :State %>
<%= select_tag :state, options_for_select(us_states, "NY"), class: 
"form-control" %>
</p>

<p class= "submit">
<%= submit_tag 'Search', name: nil, class:"btn btn-primary" %>
</p>
<% end %>

以下是错误的完整堆栈跟踪

开始GET＆＃34; /预测？utf8 =％E2％9C％93＆amp; city = new + york＆amp; state = NY＆＃34;对于127.0.0.1在2017-10-26 20:09:14 -0400 （0.2ms）SELECT＆＃34; schema_migrations＆＃34;。＆＃34; version＆＃34; FROM＆＃34; schema_migrations＆＃34; ORDER BY＆＃34; schema_migrations＆＃34;。＆＃34;版本＆＃34; ASC 由ForecastsController处理＃显示为HTML 参数：{＆＃34; utf8＆＃34; =＆gt;＆＃34;✓＆＃34;，＆＃34; city＆＃34; =＆gt;＆＃34; new york＆＃34;，＆＃34; state＆＃34; = GT;＆＃34; NY＆＃34;} 在10ms内完成500内部服务器错误（ActiveRecord：0.0ms）

URI :: InvalidURIError（错误的URI（不是URI？）：http://api.wunderground.com/api/apikey/forecast10day/q/new york / NY.json）：

app / models / weathers.rb：15：fetch_week_forecast' app/models/weathers.rb:10:in初始化＆＃39; app / controllers / forecast_controller.rb:36:in new' app/controllers/forecasts_controller.rb:36:in show＆＃39;

延续错误 错误的URI（不是URI？）：http://api.wunderground.com/api/apikey/forecast10day/q/new york / NY.json

提取的来源（第15行）： 13 14 15 16 17 18

def fetch_week_forecast(city, state)
    HTTParty.get("http://api.wunderground.com/api/apikey/forecast10day/q/#{city}/#{state}.json")
end

def week_forecast(week_weather_hash)

Answer 1

当您使用HTTParty.get时，您传递的城市和州是“dinamyc”值，因为在这种情况下，城市是“纽约”，网址是用空格创建的，这就是您收到错误的原因：

URI :: InvalidURIError（错误的URI（不是URI？）： http://api.wunderground.com/api/apikey/forecast10day/q/new 纽约/ NY.json）

您可以使用URI.encode(url)，这样，空格就会“转换”为%20，如：

http://api.wunderground.com/api/apikey/forecast10day/q/new%20york/NY.json

这是一个“有效”的网址。因此，您可以稍微调整一下fetch_week_forecast方法，例如：

def fetch_week_forecast(city, state)
  HTTParty.get(URI.encode("http://api.wunderground.com/api/apikey/forecast10day/q/#{city}/#{state}.json"))
end

如何修复rails上的ruby中的错误URI（不是URI？）：URI :: InvalidURIError

1 个答案: