Question

我有一把包含100把钥匙的字典。它看起来像这样：

{'key1': [0.0, 0.0, 0.95, 0.06, 0.01],'key2': [0.0, 0.1, 0.95,
0.26, 0.11].....'key100': [0.2, 0.0, 0.23, 0.16, 0.21]}

我希望找到最大值（在上面的示例中它将是0.95）并将所有键的所有值除以此值。基本上我会将字典转换为最大值的百分比。如果有人能告诉我如何在pandas / python中做到这一点，我将非常感激。

谢谢。

Answer 1

试试这个：

# First, find the global maximum value
max_val = 0.0
for key, value_list in d.iteritems():
    local_max = max(value_list)
    if local_max > max_val:
        max_val = local_max

# Then divide every item in every value list by the global maximum
new_dict = {}
for key, value_list in d.iteritems():
    new_dict[key] = [x/max_val for x in value_list]

Answer 2

以下是如何使用pandas做到这一点。

import pandas as pd

data = {'key1': [0.0, 0.0, 0.95, 0.06, 0.01],'key2': [0.0, 0.1, 0.95,
0.26, 0.11], 'key100': [0.2, 0.0, 0.23, 0.16, 0.21]}

df = pd.DataFrame(data)

max_value = df.max().max()

df /= max_value

Answer 3

快速写作但是＆＃34;哑巴＆＃34;如果我们遇到更高的值，那就是走dict并更新sentinel值：

maxval = 0.0
for key in d:
    for val in d[key]:
        if val > maxval:
            maxval = val


for key in d:
    d[key] = [val / maxval for val in d[key]]

Answer 4

d = {'key1':......}
from itertools import chain
max_val = max(chain.from_iterable(d.values()))
{k:[i/max_val for i in v] for k,v in d.items()}

Answer 5

尝试以下代码：

import pandas as pd
data = {'key1': [0.0, 0.0, 0.95, 0.06, 0.01],'key2': [0.0, 0.1, 0.95,
0.26, 0.11], 'key100': [0.2, 0.0, 0.23, 0.16, 0.21]}
data = pd.DataFrame(data)
max_value = data.max().unique()
data = data.divide(max_value[0])

Answer 6

试试这个：

data = {'key1': [0.0, 0.0, 0.95, 0.06, 0.01],
        'key2': [0.0, 0.1, 0.95, 0.26, 0.11],
        'key100': [0.2, 0.0, 0.23, 0.16, 0.21]}
max_in_data = max(max(vals) for vals in data.values())
data = {key: map(lambda x: x/max_in_data, vals) 
        for key, vals in data.items()}

在字典中查找最大值，并将所有值除以此值

6 个答案: